INGENIA

SRV-24

Distance error propagation

σD = √(σE² + σN²) for D from a ΔE, ΔN pair, first-order.

Reading speed
ErrorsVariance propagation

Governing equation

σD=σE2+σN2\sigma_D=\sqrt{\sigma_E^2+\sigma_N^2}

σE∈[0.5,50]\sigma_E \in \left[0.5, 50\right]

where

\sigma_E
Easting σ (mm)
\sigma_N
Northing σ (mm)
\sigma_D
Distance σ (mm)

The figure, part by part

Each numbered marker wears the color of its card. Hover a card to light the marker. Tap a marker to jump to that card. The slider walks a red point along the curve; Animate drawing traces it like a pen.

SRV-24 · gauge
00:0 / 00:08
①

Governing law — red

σD=σE2+σN2\sigma_D=\sqrt{\sigma_E^2+\sigma_N^2}

σE∈[0.5,50]\sigma_E \in \left[0.5, 50\right]

σE=0.5\sigma_E = 0.5σD=6.021\sigma_D = 6.021

②

Domain of the variable — blue

\sigma_E_{\min} = 0.5,\quad \sigma_E_{\max} = 50

σE∈[0.5,50]\sigma_E \in \left[0.5, 50\right]

σE=0.5\sigma_E = 0.5σE=0.5\sigma_E = 0.5

③

Response curve — green

σD=σE2+σN2\sigma_D=\sqrt{\sigma_E^2+\sigma_N^2}

σE∈[0.5,50]\sigma_E \in \left[0.5, 50\right]

σE=0.5\sigma_E = 0.5σD=6.021\sigma_D = 6.021

④

Rate of change — amber

dσDdσE\frac{\mathrm{d}\sigma_D}{\mathrm{d}\sigma_E}

σE∈[0.5,50]\sigma_E \in \left[0.5, 50\right]

σE=0.811\sigma_E = 0.811σD′=0.134\sigma_D^{\prime} = 0.134

Lecture brief

Historical brief

From chain and theodolite through Bowditch’s compass-rule (1802) to GPS PDOP, surveying is the propagation of small errors across a network. These sheets close traverses, reduce stadia and state map scale. This sheet (SRV-24 — Distance error propagation) is the form associated with Variance propagation. Working symbols: σE\sigma_E, σN\sigma_N →\rightarrow σD\sigma_D. σf² = (∂f/∂x)² σx² + (∂f/∂y)² σy². For D = √(ΔE²+ΔN²) this collapses to the RSS of the components when they are equal-weight.

Purpose

Purpose: compute σD\sigma_D from σE\sigma_E, σN\sigma_N in Surveying via σD=σE2+σN2\sigma_D=\sqrt{\sigma_E^2+\sigma_N^2} σD = √(σE² + σN²) for D from a ΔE, ΔN pair, first-order. Use it when a real surveying question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given σE=8.000 mm\sigma_E = 8.000\,\mathrm{mm}, σN=6.000 mm\sigma_N = 6.000\,\mathrm{mm}, the governing relation σD=σE2+σN2\sigma_D=\sqrt{\sigma_E^2+\sigma_N^2} yields σD=10.00 mm\sigma_D = 10.00\,\mathrm{mm}. An error ellipse, a distance, a σD. Move a slider: the numbers are this situation, not a canned story.

Calculator

Inputs

Outputs

  • Distance σ \sigma_D10.00 mm
Reading speed

Watch on YouTube

Free library

Full library

Free PDF / open book

YouTube channels

SRV-24 · gauge
00:0 / 00:08

Narration of this film

An error ellipse, a distance, a σD.

σf² = (∂f/∂x)² σx² + (∂f/∂y)² σy². For D = √(ΔE²+ΔN²) this collapses to the RSS of the components when they are equal-weight.

Reading speed

Watch on YouTube