INGENIA

MEC-31

Natural frequency ω=√(k/m)

ωn = √(k/m), fn = ωn/2π. One-mass, one-spring, no damper.

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VibrationUndamped SDOF

Governing equation

ωn=k/m,fn=ωn/2π\omega_n=\sqrt{k/m},\quad f_n=\omega_n/2\pi

m∈[0.1,80]m \in \left[0.1, 80\right]

where

k
Stiffness (N/m)
m
Mass (kg)
\omega_n
Natural ω (rad/s)
f_n
Natural frequency (Hz)

The figure, part by part

Each numbered marker wears the color of its card. Hover a card to light the marker. Tap a marker to jump to that card. The slider walks a red point along the curve; Animate drawing traces it like a pen.

MEC-31 · pendulum
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①

Governing law — red

ωn=k/m,fn=ωn/2π\omega_n=\sqrt{k/m},\quad f_n=\omega_n/2\pi

m∈[0.1,80]m \in \left[0.1, 80\right]

m=0.1m = 0.1ωn=22.51\omega_n = 22.51

②

Domain of the variable — blue

mmin⁡=0.1,mmax⁡=80m_{\min} = 0.1,\quad m_{\max} = 80

m∈[0.1,80]m \in \left[0.1, 80\right]

m=0.1m = 0.1m=0.1m = 0.1

③

Response curve — green

ωn=k/m,fn=ωn/2π\omega_n=\sqrt{k/m},\quad f_n=\omega_n/2\pi

m∈[0.1,80]m \in \left[0.1, 80\right]

m=0.1m = 0.1ωn=22.51\omega_n = 22.51

④

Rate of change — amber

dωndm\frac{\mathrm{d}\omega_n}{\mathrm{d}m}

m∈[0.1,80]m \in \left[0.1, 80\right]

m=0.603m = 0.603ωn′=−15.66\omega_n^{\prime} = -15.66

Lecture brief

Historical brief

Machine design grew from Coulomb torsion and Hertz contact (1881) through Soderberg fatigue and the heat-engine cycle. The lab writes shaft, bearing, contact and thermodynamic limits in SI. This sheet (MEC-31 — Natural frequency ω=√(k/m)) is the form associated with Undamped SDOF. Working symbols: kk, mm →\rightarrow ωn\omega_n, fnf_n. Newton mẍ + kx = 0. The eigenvalue of the conservative oscillator is √(k/m).

Purpose

Purpose: compute ωn\omega_n, fnf_n from kk, mm in Mechanical via ωn=k/m,fn=ωn/2π\omega_n=\sqrt{k/m},\quad f_n=\omega_n/2\pi ωn = √(k/m), fn = ωn/2π. One-mass, one-spring, no damper. Use it when a real mechanical question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given k=2000.000 N/mk = 2000.000\,\mathrm{N/m}, m=4.000 kgm = 4.000\,\mathrm{kg}, the governing relation ωn=k/m,fn=ωn/2π\omega_n=\sqrt{k/m},\quad f_n=\omega_n/2\pi yields ωn=22.36 rad/s\omega_n = 22.36\,\mathrm{rad/s}, fn=3.559 Hzf_n = 3.559\,\mathrm{Hz}. A mass on a spring, a period bar. Move a slider: the numbers are this situation, not a canned story.

Calculator

Inputs

Outputs

  • Natural ω \omega_n22.36 rad/s
  • Natural frequency f_n3.559 Hz
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MEC-31 · pendulum
00:0 / 00:08

Narration of this film

A mass on a spring, a period bar.

Newton mẍ + kx = 0. The eigenvalue of the conservative oscillator is √(k/m).

Reading speed

Watch on YouTube