INGENIA

MEC-21

Soderberg fatigue line

1/n = σm/Sy + σa/Se. The conservative mean–amplitude line through yield.

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FatigueSoderberg 1930

Governing equation

1n=σmSy+σaSe\dfrac{1}{n}=\dfrac{\sigma_m}{S_y}+\dfrac{\sigma_a}{S_e}

where

\sigma_m
Mean stress (MPa)
\sigma_a
Alternating stress (MPa)
S_y
Yield strength (MPa)
S_e
Endurance limit (MPa)
n
Factor of safety ()

Lecture brief

Historical brief

Machine design grew from Coulomb torsion and Hertz contact (1881) through Soderberg fatigue and the heat-engine cycle. The lab writes shaft, bearing, contact and thermodynamic limits in SI. This sheet (MEC-21 — Soderberg fatigue line) is the form associated with Soderberg 1930. Working symbols: σm\sigma_m, σa\sigma_a, SyS_y, SeS_e \rightarrow nn. Soderberg joins Sy on the mean axis to Se on the amplitude axis so yield is never crossed under a static load.

Purpose

Purpose: compute nn from σm\sigma_m, σa\sigma_a, SyS_y, SeS_e in Mechanical via 1n=σmSy+σaSe\dfrac{1}{n}=\dfrac{\sigma_m}{S_y}+\dfrac{\sigma_a}{S_e} 1/n = σm/Sy + σa/Se. The conservative mean–amplitude line through yield. Use it when a real mechanical question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given σm=80.000MPa\sigma_m = 80.000\,\mathrm{MPa}, σa=60.000MPa\sigma_a = 60.000\,\mathrm{MPa}, Sy=350.000MPaS_y = 350.000\,\mathrm{MPa}, Se=180.000MPaS_e = 180.000\,\mathrm{MPa}, the governing relation 1n=σmSy+σaSe\dfrac{1}{n}=\dfrac{\sigma_m}{S_y}+\dfrac{\sigma_a}{S_e} yields n=1.780n = 1.780\,\mathrm{—}. A Haigh plot, a Soderberg line, a safety tick. Move a slider: the numbers are this situation, not a canned story.

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Inputs

Outputs

  • Factor of safety n1.780
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MEC-21 · curve
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Narration of this film

A Haigh plot, a Soderberg line, a safety tick.

Soderberg joins Sy on the mean axis to Se on the amplitude axis so yield is never crossed under a static load.

Reading speed

Watch on YouTube