INGENIA

MEC-39

Petroff bearing

Lightly loaded long journal.

Reading speed
MachinesPetroff bearing

Governing equation

μ=2π2ηNrLWrc\mu=\frac{2\pi^2\eta N r L}{W}\frac{r}{c}

N∈[1,80]N \in \left[1, 80\right]

where

\eta
Viscosity (Pa·s)
N
Speed (rev/s)
r
Radius (m)
L
Length (m)
W
Load (N)
c
Clearance (mm)
\mu
Friction (—)

The figure, part by part

Each numbered marker wears the color of its card. Hover a card to light the marker. Tap a marker to jump to that card. The slider walks a red point along the curve; Animate drawing traces it like a pen.

MEC-39 · contact
00:0 / 00:08
①

Governing law — red

μ=2π2ηNrLWrc\mu=\frac{2\pi^2\eta N r L}{W}\frac{r}{c}

N∈[1,80]N \in \left[1, 80\right]

N=1N = 1μ=0.001\mu = 0.001

②

Domain of the variable — blue

Nmin⁡=1,Nmax⁡=80N_{\min} = 1,\quad N_{\max} = 80

N∈[1,80]N \in \left[1, 80\right]

N=1N = 1N=1N = 1

③

Response curve — green

μ=2π2ηNrLWrc\mu=\frac{2\pi^2\eta N r L}{W}\frac{r}{c}

N∈[1,80]N \in \left[1, 80\right]

N=1N = 1μ=0.001\mu = 0.001

④

Rate of change — amber

dμdN\frac{\mathrm{d}\mu}{\mathrm{d}N}

N∈[1,80]N \in \left[1, 80\right]

N=1.497N = 1.497μ′=0.001\mu^{\prime} = 0.001

Lecture brief

Historical brief

Machine design grew from Coulomb torsion and Hertz contact (1881) through Soderberg fatigue and the heat-engine cycle. The lab writes shaft, bearing, contact and thermodynamic limits in SI. This sheet (MEC-39 — Petroff bearing) is the form associated with Petroff bearing. Working symbols: η\eta, NN, rr, LL, WW, cc →\rightarrow μ\mu. Lightly loaded long journal. Pedagogical SI sheet with a live model and a swept parameter.

Purpose

Purpose: compute μ\mu from η\eta, NN, rr, LL, WW, cc in Mechanical via μ=2π2ηNrLWrc\mu=\frac{2\pi^2\eta N r L}{W}\frac{r}{c} Lightly loaded long journal. Use it when a real mechanical question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given η=0.080 Pa⋅s\eta = 0.080\,\mathrm{Pa·s}, N=20.000 rev/sN = 20.000\,\mathrm{rev/s}, r=0.040 mr = 0.040\,\mathrm{m}, L=0.080 mL = 0.080\,\mathrm{m}, W=2000.000 NW = 2000.000\,\mathrm{N}, c=0.080 mmc = 0.080\,\mathrm{mm}, the governing relation μ=2π2ηNrLWrc\mu=\frac{2\pi^2\eta N r L}{W}\frac{r}{c} yields μ=0.0253 —\mu = 0.0253\,\mathrm{—}. One governing identity, SI units, a single sweep on the sheet. Move a slider: the numbers are this situation, not a canned story.

Calculator

Inputs

Outputs

  • Friction \mu0.0253 —
Reading speed

Watch on YouTube

Free library

Full library

Free PDF / open book

YouTube channels

MEC-39 · contact
00:0 / 00:08

Narration of this film

One governing identity, SI units, a single sweep on the sheet.

Lightly loaded long journal. Pedagogical SI sheet with a live model and a swept parameter.

Reading speed

Watch on YouTube