INGENIA

MAT-37

Larson–Miller parameter

P = T (C + log10 tr) / 1000. Time–temperature collapse of rupture data.

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CreepLarson–Miller 1952

Governing equation

P=T(C+log⁡10tr)/1000P=T(C+\log_{10} t_r)/1000

T∈[500,1400]T \in \left[500, 1400\right]

where

T
Temperature (K)
C
Larson–Miller C (—)
t_r
Rupture time (h)
P
LMP / 1000 (—)

The figure, part by part

Each numbered marker wears the color of its card. Hover a card to light the marker. Tap a marker to jump to that card. The slider walks a red point along the curve; Animate drawing traces it like a pen.

MAT-37 · curve
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①

Governing law — red

P=T(C+log⁡10tr)/1000P=T(C+\log_{10} t_r)/1000

T∈[500,1400]T \in \left[500, 1400\right]

T=500T = 500P=11.5P = 11.5

②

Domain of the variable — blue

Tmin⁡=500,Tmax⁡=1400T_{\min} = 500,\quad T_{\max} = 1400

T∈[500,1400]T \in \left[500, 1400\right]

T=500T = 500T=500T = 500

③

Response curve — green

P=T(C+log⁡10tr)/1000P=T(C+\log_{10} t_r)/1000

T∈[500,1400]T \in \left[500, 1400\right]

T=500T = 500P=11.5P = 11.5

④

Rate of change — amber

dPdT\frac{\mathrm{d}P}{\mathrm{d}T}

T∈[500,1400]T \in \left[500, 1400\right]

T=505.7T = 505.7P′=0.023P^{\prime} = 0.023

Lecture brief

Historical brief

Hooke (1678), Hall–Petch grain size, Arrhenius activation and Paris fatigue-crack growth are the spine of materials selection. The sheets relate stress, microstructure and life. This sheet (MAT-37 — Larson–Miller parameter) is the form associated with Larson–Miller 1952. Working symbols: TT, CC, trt_r →\rightarrow PP. Arrhenius inversion: a higher T for a shorter time is equivalent to a lower T for a longer time. C ≈ 20 for steels.

Purpose

Purpose: compute PP from TT, CC, trt_r in Materials via P=T(C+log⁡10tr)/1000P=T(C+\log_{10} t_r)/1000 P = T (C + log10 tr) / 1000. Time–temperature collapse of rupture data. Use it when a real materials question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given T=900.000 KT = 900.000\,\mathrm{K}, C=20.000 —C = 20.000\,\mathrm{—}, tr=1000.000 ht_r = 1000.000\,\mathrm{h}, the governing relation P=T(C+log⁡10tr)/1000P=T(C+\log_{10} t_r)/1000 yields P=20.70 —P = 20.70\,\mathrm{—}. A master curve, a T–t pair, a P tick. Move a slider: the numbers are this situation, not a canned story.

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Inputs

Outputs

  • LMP / 1000 P20.70 —
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MAT-37 · curve
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Narration of this film

A master curve, a T–t pair, a P tick.

Arrhenius inversion: a higher T for a shorter time is equivalent to a lower T for a longer time. C ≈ 20 for steels.

Reading speed

Watch on YouTube