INGENIA

MAT-36

Hollomon hardening

σ = K ε^n. Power-law true stress–strain in the plastic range.

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PlasticityHollomon 1945

Governing equation

σ=Kεn\sigma=K\varepsilon^n

ε∈[0.001,0.6]\varepsilon \in \left[0.001, 0.6\right]

where

K
Strength coefficient (MPa)
\varepsilon
True strain (—)
n
Hardening n (—)
\sigma
True stress (MPa)

The figure, part by part

Each numbered marker wears the color of its card. Hover a card to light the marker. Tap a marker to jump to that card. The slider walks a red point along the curve; Animate drawing traces it like a pen.

MAT-36 · curve
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①

Governing law — red

σ=Kεn\sigma=K\varepsilon^n

ε∈[0.001,0.6]\varepsilon \in \left[0.001, 0.6\right]

ε=0.001\varepsilon = 0.001σ=201\sigma = 201

②

Domain of the variable — blue

εmin⁡=0.001,εmax⁡=0.6\varepsilon_{\min} = 0.001,\quad \varepsilon_{\max} = 0.6

ε∈[0.001,0.6]\varepsilon \in \left[0.001, 0.6\right]

ε=0.001\varepsilon = 0.001ε=0.001\varepsilon = 0.001

③

Response curve — green

σ=Kεn\sigma=K\varepsilon^n

ε∈[0.001,0.6]\varepsilon \in \left[0.001, 0.6\right]

ε=0.001\varepsilon = 0.001σ=201\sigma = 201

④

Rate of change — amber

dσdε\frac{\mathrm{d}\sigma}{\mathrm{d}\varepsilon}

ε∈[0.001,0.6]\varepsilon \in \left[0.001, 0.6\right]

ε=0.005\varepsilon = 0.005σ′=14280.8\sigma^{\prime} = 14280.8

Lecture brief

Historical brief

Hooke (1678), Hall–Petch grain size, Arrhenius activation and Paris fatigue-crack growth are the spine of materials selection. The sheets relate stress, microstructure and life. This sheet (MAT-36 — Hollomon hardening) is the form associated with Hollomon 1945. Working symbols: KK, ε\varepsilon, nn →\rightarrow σ\sigma. Hollomon fitted the plastic branch of many metals to a power law. n is the strain-hardening exponent, K the strength coefficient.

Purpose

Purpose: compute σ\sigma from KK, ε\varepsilon, nn in Materials via σ=Kεn\sigma=K\varepsilon^n σ = K ε^n. Power-law true stress–strain in the plastic range. Use it when a real materials question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given K=800.000 MPaK = 800.000\,\mathrm{MPa}, ε=0.080 —\varepsilon = 0.080\,\mathrm{—}, n=0.200 —n = 0.200\,\mathrm{—}, the governing relation σ=Kεn\sigma=K\varepsilon^n yields σ=482.7 MPa\sigma = 482.7\,\mathrm{MPa}. A log–log σ–ε line, an n slope. Move a slider: the numbers are this situation, not a canned story.

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Inputs

Outputs

  • True stress \sigma482.7 MPa
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MAT-36 · curve
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Narration of this film

A log–log σ–ε line, an n slope.

Hollomon fitted the plastic branch of many metals to a power law. n is the strain-hardening exponent, K the strength coefficient.

Reading speed

Watch on YouTube