INGENIA

MAT-35

Endurance-limit estimate

Se ≈ 0.5 Sut · ka kb kc. Marin factors on a rotating-beam limit.

Reading speed
FatigueMarin

Governing equation

Se=0.5SutkakbkcS_e=0.5 S_{ut} k_a k_b k_c

Sut∈[200,1400]S_{ut} \in \left[200, 1400\right]

where

S_{ut}
Ultimate tensile (MPa)
k_a
Surface factor (—)
k_b
Size factor (—)
k_c
Load factor (—)
S_e
Endurance limit (MPa)

The figure, part by part

Each numbered marker wears the color of its card. Hover a card to light the marker. Tap a marker to jump to that card. The slider walks a red point along the curve; Animate drawing traces it like a pen.

MAT-35 · curve
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①

Governing law — red

Se=0.5SutkakbkcS_e=0.5 S_{ut} k_a k_b k_c

Sut∈[200,1400]S_{ut} \in \left[200, 1400\right]

Sut=200S_{ut} = 200Se=72S_e = 72

②

Domain of the variable — blue

S_{ut}_{\min} = 200,\quad S_{ut}_{\max} = 1400

Sut∈[200,1400]S_{ut} \in \left[200, 1400\right]

Sut=200S_{ut} = 200Sut=200S_{ut} = 200

③

Response curve — green

Se=0.5SutkakbkcS_e=0.5 S_{ut} k_a k_b k_c

Sut∈[200,1400]S_{ut} \in \left[200, 1400\right]

Sut=200S_{ut} = 200Se=72S_e = 72

④

Rate of change — amber

dSedSut\frac{\mathrm{d}S_e}{\mathrm{d}S_{ut}}

Sut∈[200,1400]S_{ut} \in \left[200, 1400\right]

Sut=207.5S_{ut} = 207.5Se′=0.36S_e^{\prime} = 0.36

Lecture brief

Historical brief

Hooke (1678), Hall–Petch grain size, Arrhenius activation and Paris fatigue-crack growth are the spine of materials selection. The sheets relate stress, microstructure and life. This sheet (MAT-35 — Endurance-limit estimate) is the form associated with Marin. Working symbols: SutS_{ut}, kak_a, kbk_b, kck_c →\rightarrow SeS_e. For steels the rotating-beam endurance is about half the ultimate. Surface, size and load factors knock it down.

Purpose

Purpose: compute SeS_e from SutS_{ut}, kak_a, kbk_b, kck_c in Materials via Se=0.5SutkakbkcS_e=0.5 S_{ut} k_a k_b k_c Se ≈ 0.5 Sut · ka kb kc. Marin factors on a rotating-beam limit. Use it when a real materials question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given Sut=600.000 MPaS_{ut} = 600.000\,\mathrm{MPa}, ka=0.800 —k_a = 0.800\,\mathrm{—}, kb=0.900 —k_b = 0.900\,\mathrm{—}, kc=1.000 —k_c = 1.000\,\mathrm{—}, the governing relation Se=0.5SutkakbkcS_e=0.5 S_{ut} k_a k_b k_c yields Se=216.0 MPaS_e = 216.0\,\mathrm{MPa}. An S–N floor, three reduction ticks. Move a slider: the numbers are this situation, not a canned story.

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Inputs

Outputs

  • Endurance limit S_e216.0 MPa
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MAT-35 · curve
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Narration of this film

An S–N floor, three reduction ticks.

For steels the rotating-beam endurance is about half the ultimate. Surface, size and load factors knock it down.

Reading speed

Watch on YouTube