INGENIA

MAT-25

Considère necking strain

For Hollomon σ = K ε^n, necking starts at εt = n. Load maximum dP = 0.

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PlasticityConsidère 1885

Governing equation

εu=n,σu=Knn\varepsilon_{\mathrm{u}}=n,\quad\sigma_{\mathrm{u}}=K n^n

n∈[0.05,0.5]n \in \left[0.05, 0.5\right]

where

K
Strength coefficient (MPa)
n
Strain-hardening n (—)
\varepsilon_u
Necking strain (—)
\sigma_u
True stress at neck (MPa)

The figure, part by part

Each numbered marker wears the color of its card. Hover a card to light the marker. Tap a marker to jump to that card. The slider walks a red point along the curve; Animate drawing traces it like a pen.

MAT-25 · curve
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①

Governing law — red

εu=n,σu=Knn\varepsilon_{\mathrm{u}}=n,\quad\sigma_{\mathrm{u}}=K n^n

n∈[0.05,0.5]n \in \left[0.05, 0.5\right]

n=0.05n = 0.05εu=0.05\varepsilon_u = 0.05

②

Domain of the variable — blue

nmin⁡=0.05,nmax⁡=0.5n_{\min} = 0.05,\quad n_{\max} = 0.5

n∈[0.05,0.5]n \in \left[0.05, 0.5\right]

n=0.05n = 0.05n=0.05n = 0.05

③

Response curve — green

εu=n,σu=Knn\varepsilon_{\mathrm{u}}=n,\quad\sigma_{\mathrm{u}}=K n^n

n∈[0.05,0.5]n \in \left[0.05, 0.5\right]

n=0.05n = 0.05εu=0.05\varepsilon_u = 0.05

④

Rate of change — amber

dεudn\frac{\mathrm{d}\varepsilon_u}{\mathrm{d}n}

n∈[0.05,0.5]n \in \left[0.05, 0.5\right]

n=0.053n = 0.053εu′=1\varepsilon_u^{\prime} = 1

Lecture brief

Historical brief

Hooke (1678), Hall–Petch grain size, Arrhenius activation and Paris fatigue-crack growth are the spine of materials selection. The sheets relate stress, microstructure and life. This sheet (MAT-25 — Considère necking strain) is the form associated with Considère 1885. Working symbols: KK, nn →\rightarrow εu\varepsilon_u, σu\sigma_u. Considère: necking when dσ/dε = σ. Power-law hardening σ = K ε^n satisfies that identity at ε = n.

Purpose

Purpose: compute εu\varepsilon_u, σu\sigma_u from KK, nn in Materials via εu=n,σu=Knn\varepsilon_{\mathrm{u}}=n,\quad\sigma_{\mathrm{u}}=K n^n For Hollomon σ = K ε^n, necking starts at εt = n. Load maximum dP = 0. Use it when a real materials question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given K=800.000 MPaK = 800.000\,\mathrm{MPa}, n=0.220 —n = 0.220\,\mathrm{—}, the governing relation εu=n,σu=Knn\varepsilon_{\mathrm{u}}=n,\quad\sigma_{\mathrm{u}}=K n^n yields εu=0.220 —\varepsilon_u = 0.220\,\mathrm{—}, σu=573.4 MPa\sigma_u = 573.4\,\mathrm{MPa}. A tensile curve, a load peak, a neck. Move a slider: the numbers are this situation, not a canned story.

Calculator

Inputs

Outputs

  • Necking strain \varepsilon_u0.220 —
  • True stress at neck \sigma_u573.4 MPa
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MAT-25 · curve
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Narration of this film

A tensile curve, a load peak, a neck.

Considère: necking when dσ/dε = σ. Power-law hardening σ = K ε^n satisfies that identity at ε = n.

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