INGENIA

MAT-07

Griffith brittle-fracture stress

σf = √(2 E γ /(π a)) for a through crack.

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FractureGriffith 1921

Governing equation

σf=2Eγsπa\sigma_f=\sqrt{\dfrac{2E\gamma_s}{\pi a}}

a∈[0.01,20]a \in \left[0.01, 20\right]

where

E
Modulus (GPa)
\gamma_s
Surface energy (J/m²)
a
Half-crack length (mm)
\sigma_f
Fracture stress (MPa)

The figure, part by part

Each numbered marker wears the color of its card. Hover a card to light the marker. Tap a marker to jump to that card. The slider walks a red point along the curve; Animate drawing traces it like a pen.

MAT-07 · curve
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①

Governing law — red

σf=2Eγsπa\sigma_f=\sqrt{\dfrac{2E\gamma_s}{\pi a}}

a∈[0.01,20]a \in \left[0.01, 20\right]

a=0.01a = 0.01σf=66.76\sigma_f = 66.76

②

Domain of the variable — blue

amin⁡=0.01,amax⁡=20a_{\min} = 0.01,\quad a_{\max} = 20

a∈[0.01,20]a \in \left[0.01, 20\right]

a=0.01a = 0.01a=0.01a = 0.01

③

Response curve — green

σf=2Eγsπa\sigma_f=\sqrt{\dfrac{2E\gamma_s}{\pi a}}

a∈[0.01,20]a \in \left[0.01, 20\right]

a=0.01a = 0.01σf=66.76\sigma_f = 66.76

④

Rate of change — amber

dσfda\frac{\mathrm{d}\sigma_f}{\mathrm{d}a}

a∈[0.01,20]a \in \left[0.01, 20\right]

a=0.136a = 0.136σf′=−213.6\sigma_f^{\prime} = -213.6

Lecture brief

Historical brief

Hooke (1678), Hall–Petch grain size, Arrhenius activation and Paris fatigue-crack growth are the spine of materials selection. The sheets relate stress, microstructure and life. This sheet (MAT-07 — Griffith brittle-fracture stress) is the form associated with Griffith 1921. Working symbols: EE, γs\gamma_s, aa →\rightarrow σf\sigma_f. Griffith equated the elastic energy released by extending a crack to the surface energy created, obtaining 1/√a strength.

Purpose

Purpose: compute σf\sigma_f from EE, γs\gamma_s, aa in Materials via σf=2Eγsπa\sigma_f=\sqrt{\dfrac{2E\gamma_s}{\pi a}} σf = √(2 E γ /(π a)) for a through crack. Use it when a real materials question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given E=70.000 GPaE = 70.000\,\mathrm{GPa}, γs=1.000 J/m2\gamma_s = 1.000\,\mathrm{J/m^{2}}, a=0.500 mma = 0.500\,\mathrm{mm}, the governing relation σf=2Eγsπa\sigma_f=\sqrt{\dfrac{2E\gamma_s}{\pi a}} yields σf=9.441 MPa\sigma_f = 9.441\,\mathrm{MPa}. Infinite plate, through crack 2a, plane stress, brittle. Move a slider: the numbers are this situation, not a canned story.

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Inputs

Outputs

  • Fracture stress \sigma_f9.441 MPa
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Narration of this film

Infinite plate, through crack 2a, plane stress, brittle.

Griffith equated the elastic energy released by extending a crack to the surface energy created, obtaining 1/√a strength.

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