INGENIA

INO-10

Spin-only magnetic moment

μso = √(n(n+2)) BM. Unpaired-electron moment.

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MagnetismSpin-only

Governing equation

μso=n(n+2)\mu_{so}=\sqrt{n(n+2)}

n∈[0,7]n \in \left[0, 7\right]

where

n
Unpaired electrons (—)
\mu_{so}
Spin-only moment (\mu_B)

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INO-10 · gauge
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①

Governing law — red

μso=n(n+2)\mu_{so}=\sqrt{n(n+2)}

n∈[0,7]n \in \left[0, 7\right]

n=0n = 0μso=0\mu_{so} = 0

②

Domain of the variable — blue

nmin⁡=0,nmax⁡=7n_{\min} = 0,\quad n_{\max} = 7

n∈[0,7]n \in \left[0, 7\right]

n=0n = 0n=0n = 0

③

Response curve — green

μso=n(n+2)\mu_{so}=\sqrt{n(n+2)}

n∈[0,7]n \in \left[0, 7\right]

n=0n = 0μso=0\mu_{so} = 0

④

Rate of change — amber

dμsodn\frac{\mathrm{d}\mu_{so}}{\mathrm{d}n}

n∈[0,7]n \in \left[0, 7\right]

n=0.044n = 0.044μso′=4.87\mu_{so}^{\prime} = 4.87

Lecture brief

Historical brief

Pauling and Allred–Rochow electronegativity, Kapustinskii lattice energy, CFSE and Goldschmidt radii organise the periodic solid. The sheets predict bond character and crystal packing. This sheet (INO-10 — Spin-only magnetic moment) is the form associated with Spin-only. Working symbols: nn →\rightarrow μso\mu_{so}. Orbital angular momentum is quenched in many Oh complexes. n unpaired electrons.

Purpose

Purpose: compute μso\mu_{so} from nn in Inorganic chemistry via μso=n(n+2)\mu_{so}=\sqrt{n(n+2)} μso = √(n(n+2)) BM. Unpaired-electron moment. Use it when a real inorganic chemistry question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given n=5.000 —n = 5.000\,\mathrm{—}, the governing relation μso=n(n+2)\mu_{so}=\sqrt{n(n+2)} yields μso=5.916 muB\mu_{so} = 5.916\,\mathrm{mu_B}. Enter the number of unpaired electrons. Move a slider: the numbers are this situation, not a canned story.

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Inputs

Outputs

  • Spin-only moment \mu_{so}5.916 \mu_B
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Narration of this film

Enter the number of unpaired electrons.

Orbital angular momentum is quenched in many Oh complexes. n unpaired electrons.

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