INGENIA

INO-26

Spin-only μ

First-row ions.

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Inorganicspin-only

Governing equation

mu=sqrtn(n+2)\\mu=\\sqrt{n(n+2)}

n∈[0,5]n \in \left[0, 5\right]

where

n
Unpaired (—)
\mu
μ (\mu_B)

The figure, part by part

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INO-26 · gauge
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①

Governing law — red

mu=sqrtn(n+2)\\mu=\\sqrt{n(n+2)}

n∈[0,5]n \in \left[0, 5\right]

n=0n = 0μ=0\mu = 0

②

Domain of the variable — blue

nmin⁡=0,nmax⁡=5n_{\min} = 0,\quad n_{\max} = 5

n∈[0,5]n \in \left[0, 5\right]

n=0n = 0n=0n = 0

③

Response curve — green

mu=sqrtn(n+2)\\mu=\\sqrt{n(n+2)}

n∈[0,5]n \in \left[0, 5\right]

n=0n = 0μ=0\mu = 0

④

Rate of change — amber

dμdn\frac{\mathrm{d}\mu}{\mathrm{d}n}

n∈[0,5]n \in \left[0, 5\right]

n=0.031n = 0.031μ′=5.727\mu^{\prime} = 5.727

Lecture brief

Historical brief

Pauling and Allred–Rochow electronegativity, Kapustinskii lattice energy, CFSE and Goldschmidt radii organise the periodic solid. The sheets predict bond character and crystal packing. This sheet (INO-26 — Spin-only μ) is the form associated with spin-only. Working symbols: nn →\rightarrow μ\mu. First-row ions.

Purpose

Purpose: compute μ\mu from nn in Inorganic chemistry via mu=sqrtn(n+2)\\mu=\\sqrt{n(n+2)} First-row ions. Use it when a real inorganic chemistry question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given n=3.000 —n = 3.000\,\mathrm{—}, the governing relation mu=sqrtn(n+2)\\mu=\\sqrt{n(n+2)} yields μ=3.87 muB\mu = 3.87\,\mathrm{mu_B}. First-row ions. Move a slider: the numbers are this situation, not a canned story.

Calculator

Inputs

Outputs

  • μ \mu3.87 \mu_B
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INO-26 · gauge
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Narration of this film

First-row ions.

First-row ions.

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