INGENIA

INO-22

Hard–soft interaction snapshot

E ≈ −(χA − χB)² / (2(ηA + ηB)). Charge-transfer stabilisation.

Reading speed
AcidityPearson–Parr

Governing equation

E=−(χA−χB)22(ηA+ηB)E=-\dfrac{(\chi_A-\chi_B)^2}{2(\eta_A+\eta_B)}

χA∈[2,15]\chi_A \in \left[2, 15\right]

where

\chi_A
EN of A (eV)
\chi_B
EN of B (eV)
\eta_A
Hardness of A (eV)
\eta_B
Hardness of B (eV)
E
Stabilisation (eV)

The figure, part by part

Each numbered marker wears the color of its card. Hover a card to light the marker. Tap a marker to jump to that card. The slider walks a red point along the curve; Animate drawing traces it like a pen.

INO-22 · gauge
00:0 / 00:08
①

Governing law — red

E=−(χA−χB)22(ηA+ηB)E=-\dfrac{(\chi_A-\chi_B)^2}{2(\eta_A+\eta_B)}

χA∈[2,15]\chi_A \in \left[2, 15\right]

χA=2\chi_A = 2E=−2E = -2

②

Domain of the variable — blue

\chi_A_{\min} = 2,\quad \chi_A_{\max} = 15

χA∈[2,15]\chi_A \in \left[2, 15\right]

χA=2\chi_A = 2χA=2\chi_A = 2

③

Response curve — green

E=−(χA−χB)22(ηA+ηB)E=-\dfrac{(\chi_A-\chi_B)^2}{2(\eta_A+\eta_B)}

χA∈[2,15]\chi_A \in \left[2, 15\right]

χA=2\chi_A = 2E=−2E = -2

④

Rate of change — amber

dEdχA\frac{\mathrm{d}E}{\mathrm{d}\chi_A}

χA∈[2,15]\chi_A \in \left[2, 15\right]

χA=2.082\chi_A = 2.082E′=0.658E^{\prime} = 0.658

Lecture brief

Historical brief

Pauling and Allred–Rochow electronegativity, Kapustinskii lattice energy, CFSE and Goldschmidt radii organise the periodic solid. The sheets predict bond character and crystal packing. This sheet (INO-22 — Hard–soft interaction snapshot) is the form associated with Pearson–Parr. Working symbols: χA\chi_A, χB\chi_B, ηA\eta_A, ηB\eta_B →\rightarrow EE. The Klopman–Parr formula: a large EN mismatch on two soft (small-η) partners is strongly stabilising.

Purpose

Purpose: compute EE from χA\chi_A, χB\chi_B, ηA\eta_A, ηB\eta_B in Inorganic chemistry via E=−(χA−χB)22(ηA+ηB)E=-\dfrac{(\chi_A-\chi_B)^2}{2(\eta_A+\eta_B)} E ≈ −(χA − χB)² / (2(ηA + ηB)). Charge-transfer stabilisation. Use it when a real inorganic chemistry question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given χA=6.000 eV\chi_A = 6.000\,\mathrm{eV}, χB=8.000 eV\chi_B = 8.000\,\mathrm{eV}, ηA=5.000 eV\eta_A = 5.000\,\mathrm{eV}, ηB=4.000 eV\eta_B = 4.000\,\mathrm{eV}, the governing relation E=−(χA−χB)22(ηA+ηB)E=-\dfrac{(\chi_A-\chi_B)^2}{2(\eta_A+\eta_B)} yields E=−0.2222 eVE = -0.2222\,\mathrm{eV}. Two partners, Mulliken χ and hardness η in eV. Move a slider: the numbers are this situation, not a canned story.

Calculator

Inputs

Outputs

  • Stabilisation E-0.2222 eV
Reading speed

Watch on YouTube

Free library

Full library

Free PDF / open book

YouTube channels

INO-22 · gauge
00:0 / 00:08

Narration of this film

Two partners, Mulliken χ and hardness η in eV.

The Klopman–Parr formula: a large EN mismatch on two soft (small-η) partners is strongly stabilising.

Reading speed

Watch on YouTube