INGENIA

HYD-04

Rectangular weir discharge

Q = (2/3) Cd L √(2g) H^{3/2} for a sharp-crested weir.

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WeirsKindsvater–CarterISO 1438

Governing equation

Q=23CdL2g H3/2Q=\dfrac{2}{3}C_d L\sqrt{2g}\,H^{3/2}

H∈[0.02,1.5]H \in \left[0.02, 1.5\right]

where

C_d
Discharge coefficient (—)
L
Crest length (m)
H
Head on crest (m)
Q
Discharge (m³/s)

The figure, part by part

Each numbered marker wears the color of its card. Hover a card to light the marker. Tap a marker to jump to that card. The slider walks a red point along the curve; Animate drawing traces it like a pen.

HYD-04 · pipe
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①

Governing law — red

Q=23CdL2g H3/2Q=\dfrac{2}{3}C_d L\sqrt{2g}\,H^{3/2}

H∈[0.02,1.5]H \in \left[0.02, 1.5\right]

H=0.02H = 0.02Q=0.008Q = 0.008

②

Domain of the variable — blue

Hmin⁡=0.02,Hmax⁡=1.5H_{\min} = 0.02,\quad H_{\max} = 1.5

H∈[0.02,1.5]H \in \left[0.02, 1.5\right]

H=0.02H = 0.02H=0.02H = 0.02

③

Response curve — green

Q=23CdL2g H3/2Q=\dfrac{2}{3}C_d L\sqrt{2g}\,H^{3/2}

H∈[0.02,1.5]H \in \left[0.02, 1.5\right]

H=0.02H = 0.02Q=0.008Q = 0.008

④

Rate of change — amber

dQdH\frac{\mathrm{d}Q}{\mathrm{d}H}

H∈[0.02,1.5]H \in \left[0.02, 1.5\right]

H=0.029H = 0.029Q′=0.702Q^{\prime} = 0.702

Lecture brief

Historical brief

Open-channel and pipe flow were written by Chezy, Manning, Darcy and Weisbach in the nineteenth century, then Bakhmeteff and Bélanger on the hydraulic jump. The sheets compute conveyance, head loss and gradually varied profiles. This sheet (HYD-04 — Rectangular weir discharge) is the form associated with Kindsvater–Carter · ISO 1438. Working symbols: CdC_d, LL, HH →\rightarrow QQ. Torricelli efflux integrated across a rectangular nappe gives the 3/2 power of head; Cd absorbs contraction and viscosity.

Purpose

Purpose: compute QQ from CdC_d, LL, HH in Hydraulics via Q=23CdL2g H3/2Q=\dfrac{2}{3}C_d L\sqrt{2g}\,H^{3/2} Q = (2/3) Cd L √(2g) H^{3/2} for a sharp-crested weir. Use it when a real hydraulics question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given Cd=0.620 —C_d = 0.620\,\mathrm{—}, L=1.500 mL = 1.500\,\mathrm{m}, H=0.250 mH = 0.250\,\mathrm{m}, the governing relation Q=23CdL2g H3/2Q=\dfrac{2}{3}C_d L\sqrt{2g}\,H^{3/2} yields Q=0.343 m3/sQ = 0.343\,\mathrm{m^{3}/s}. Fully ventilated nappe, neglected velocity of approach. Move a slider: the numbers are this situation, not a canned story.

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Inputs

Outputs

  • Discharge Q0.343 m³/s
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HYD-04 · pipe
00:0 / 00:08

Narration of this film

Fully ventilated nappe, neglected velocity of approach.

Torricelli efflux integrated across a rectangular nappe gives the 3/2 power of head; Cd absorbs contraction and viscosity.

Reading speed

Watch on YouTube