INGENIA

HYD-04

Rectangular weir discharge

Q = (2/3) Cd L √(2g) H^{3/2} for a sharp-crested weir.

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WeirsKindsvater–CarterISO 1438

Governing equation

Q=23CdL2gH3/2Q=\dfrac{2}{3}C_d L\sqrt{2g}\,H^{3/2}

where

C_d
Discharge coefficient ()
L
Crest length (m)
H
Head on crest (m)
Q
Discharge (m³/s)

Lecture brief

Historical brief

Open-channel and pipe flow were written by Chezy, Manning, Darcy and Weisbach in the nineteenth century, then Bakhmeteff and Bélanger on the hydraulic jump. The sheets compute conveyance, head loss and gradually varied profiles. This sheet (HYD-04 — Rectangular weir discharge) is the form associated with Kindsvater–Carter · ISO 1438. Working symbols: CdC_d, LL, HH \rightarrow QQ. Torricelli efflux integrated across a rectangular nappe gives the 3/2 power of head; Cd absorbs contraction and viscosity.

Purpose

Purpose: compute QQ from CdC_d, LL, HH in Hydraulics via Q=23CdL2gH3/2Q=\dfrac{2}{3}C_d L\sqrt{2g}\,H^{3/2} Q = (2/3) Cd L √(2g) H^{3/2} for a sharp-crested weir. Use it when a real hydraulics question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given Cd=0.620C_d = 0.620\,\mathrm{—}, L=1.500mL = 1.500\,\mathrm{m}, H=0.250mH = 0.250\,\mathrm{m}, the governing relation Q=23CdL2gH3/2Q=\dfrac{2}{3}C_d L\sqrt{2g}\,H^{3/2} yields Q=0.343m3/sQ = 0.343\,\mathrm{m^{3}/s}. Fully ventilated nappe, neglected velocity of approach. Move a slider: the numbers are this situation, not a canned story.

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Inputs

Outputs

  • Discharge Q0.343 m³/s
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HYD-04 · pipe
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Narration of this film

Fully ventilated nappe, neglected velocity of approach.

Torricelli efflux integrated across a rectangular nappe gives the 3/2 power of head; Cd absorbs contraction and viscosity.

Reading speed

Watch on YouTube