INGENIA

HYD-09

Manning discharge

Q = (1/n) A R^{2/3} S^{1/2}. Uniform open-channel flow.

Reading speed
Open channelManning

Governing equation

Q=1nAR2/3S1/2Q=\dfrac1n A R^{2/3} S^{1/2}

S∈[1×10−4,0.02]S \in \left[1\times 10^{-4}, 0.02\right]

where

n
Roughness n (—)
A
Area (m²)
R
Hydraulic radius (m)
S
Slope (—)
Q
Discharge (m³/s)

The figure, part by part

Each numbered marker wears the color of its card. Hover a card to light the marker. Tap a marker to jump to that card. The slider walks a red point along the curve; Animate drawing traces it like a pen.

HYD-09 · pipe
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①

Governing law — red

Q=1nAR2/3S1/2Q=\dfrac1n A R^{2/3} S^{1/2}

S∈[1×10−4,0.02]S \in \left[1\times 10^{-4}, 0.02\right]

S=1×10−4S = 1\times 10^{-4}Q=2.652Q = 2.652

②

Domain of the variable — blue

Smin⁡=1×10−4,Smax⁡=0.02S_{\min} = 1\times 10^{-4},\quad S_{\max} = 0.02

S∈[1×10−4,0.02]S \in \left[1\times 10^{-4}, 0.02\right]

S=1×10−4S = 1\times 10^{-4}S=1×10−4S = 1\times 10^{-4}

③

Response curve — green

Q=1nAR2/3S1/2Q=\dfrac1n A R^{2/3} S^{1/2}

S∈[1×10−4,0.02]S \in \left[1\times 10^{-4}, 0.02\right]

S=1×10−4S = 1\times 10^{-4}Q=2.652Q = 2.652

④

Rate of change — amber

dQdS\frac{\mathrm{d}Q}{\mathrm{d}S}

S∈[1×10−4,0.02]S \in \left[1\times 10^{-4}, 0.02\right]

S=2.25×10−4S = 2.25\times 10^{-4}Q′=9233.7Q^{\prime} = 9233.7

Lecture brief

Historical brief

Open-channel and pipe flow were written by Chezy, Manning, Darcy and Weisbach in the nineteenth century, then Bakhmeteff and Bélanger on the hydraulic jump. The sheets compute conveyance, head loss and gradually varied profiles. This sheet (HYD-09 — Manning discharge) is the form associated with Manning. Working symbols: nn, AA, RR, SS →\rightarrow QQ. n is roughness; R = A/P hydraulic radius; S the friction slope.

Purpose

Purpose: compute QQ from nn, AA, RR, SS in Hydraulics via Q=1nAR2/3S1/2Q=\dfrac1n A R^{2/3} S^{1/2} Q = (1/n) A R^{2/3} S^{1/2}. Uniform open-channel flow. Use it when a real hydraulics question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given n=0.013 —n = 0.013\,\mathrm{—}, A=4.000 m2A = 4.000\,\mathrm{m^{2}}, R=0.800 mR = 0.800\,\mathrm{m}, S=0.001 —S = 0.001\,\mathrm{—}, the governing relation Q=1nAR2/3S1/2Q=\dfrac1n A R^{2/3} S^{1/2} yields Q=8.385 m3/sQ = 8.385\,\mathrm{m^{3}/s}. A prismatic channel, a water surface, a discharge. Move a slider: the numbers are this situation, not a canned story.

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Inputs

Outputs

  • Discharge Q8.385 m³/s
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HYD-09 · pipe
00:0 / 00:08

Narration of this film

A prismatic channel, a water surface, a discharge.

n is roughness; R = A/P hydraulic radius; S the friction slope.

Reading speed

Watch on YouTube