INGENIA

HYD-24

Hydraulic jump sequent depth

y2/y1 = ½ (−1 + √(1+8 Fr1²)). Momentum across a rapid jump.

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Open channelBélanger

Governing equation

y2y1=12(−1+1+8Fr12)\dfrac{y_2}{y_1}=\tfrac12\bigl(-1+\sqrt{1+8\mathrm{Fr}_1^2}\bigr)

Fr1∈[1.1,9]\mathrm{Fr}_1 \in \left[1.1, 9\right]

where

y_1
Upstream depth (m)
\mathrm{Fr}_1
Upstream Froude (—)
y_2
Sequent depth (m)
y_2/y_1
Ratio (—)

The figure, part by part

Each numbered marker wears the color of its card. Hover a card to light the marker. Tap a marker to jump to that card. The slider walks a red point along the curve; Animate drawing traces it like a pen.

HYD-24 · wave
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①

Governing law — red

y2y1=12(−1+1+8Fr12)\dfrac{y_2}{y_1}=\tfrac12\bigl(-1+\sqrt{1+8\mathrm{Fr}_1^2}\bigr)

Fr1∈[1.1,9]\mathrm{Fr}_1 \in \left[1.1, 9\right]

Fr1=1.1\mathrm{Fr}_1 = 1.1y2=0.454y_2 = 0.454

②

Domain of the variable — blue

\mathrm{Fr}_1_{\min} = 1.1,\quad \mathrm{Fr}_1_{\max} = 9

Fr1∈[1.1,9]\mathrm{Fr}_1 \in \left[1.1, 9\right]

Fr1=1.1\mathrm{Fr}_1 = 1.1Fr1=1.1\mathrm{Fr}_1 = 1.1

③

Response curve — green

y2y1=12(−1+1+8Fr12)\dfrac{y_2}{y_1}=\tfrac12\bigl(-1+\sqrt{1+8\mathrm{Fr}_1^2}\bigr)

Fr1∈[1.1,9]\mathrm{Fr}_1 \in \left[1.1, 9\right]

Fr1=1.1\mathrm{Fr}_1 = 1.1y2=0.454y_2 = 0.454

④

Rate of change — amber

dy2dFr1\frac{\mathrm{d}y_2}{\mathrm{d}\mathrm{Fr}_1}

Fr1∈[1.1,9]\mathrm{Fr}_1 \in \left[1.1, 9\right]

Fr1=1.15\mathrm{Fr}_1 = 1.15y2′=0.541y_2^{\prime} = 0.541

Lecture brief

Historical brief

Open-channel and pipe flow were written by Chezy, Manning, Darcy and Weisbach in the nineteenth century, then Bakhmeteff and Bélanger on the hydraulic jump. The sheets compute conveyance, head loss and gradually varied profiles. This sheet (HYD-24 — Hydraulic jump sequent depth) is the form associated with Bélanger. Working symbols: y1y_1, Fr1\mathrm{Fr}_1 →\rightarrow y2y_2, y2/y1y_2/y_1. Bélanger: horizontal hydrostatic force plus momentum flux, friction neglected on a short apron.

Purpose

Purpose: compute y2y_2, y2/y1y_2/y_1 from y1y_1, Fr1\mathrm{Fr}_1 in Hydraulics via y2y1=12(−1+1+8Fr12)\dfrac{y_2}{y_1}=\tfrac12\bigl(-1+\sqrt{1+8\mathrm{Fr}_1^2}\bigr) y2/y1 = ½ (−1 + √(1+8 Fr1²)). Momentum across a rapid jump. Use it when a real hydraulics question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given y1=0.400 my_1 = 0.400\,\mathrm{m}, Fr1=3.500 —\mathrm{Fr}_1 = 3.500\,\mathrm{—}, the governing relation y2y1=12(−1+1+8Fr12)\dfrac{y_2}{y_1}=\tfrac12\bigl(-1+\sqrt{1+8\mathrm{Fr}_1^2}\bigr) yields y2=1.790 my_2 = 1.790\,\mathrm{m}, y2/y1=4.47 —y_2/y_1 = 4.47\,\mathrm{—}. A supercritical jet, a roller, a sequent depth. Move a slider: the numbers are this situation, not a canned story.

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Inputs

Outputs

  • Sequent depth y_21.790 m
  • Ratio y_2/y_14.47 —
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HYD-24 · wave
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Narration of this film

A supercritical jet, a roller, a sequent depth.

Bélanger: horizontal hydrostatic force plus momentum flux, friction neglected on a short apron.

Reading speed

Watch on YouTube