INGENIA

HYD-32

Francis contracted weir

Q = 1.84 (L − 0.1 n H) H^{3/2} (SI). End contractions n = 0, 1 or 2.

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WeirsFrancis

Governing equation

Q=1.84 (L−0.1nH)H3/2Q=1.84\,(L-0.1 n H)H^{3/2}

H∈[0.04,1.2]H \in \left[0.04, 1.2\right]

where

L
Crest length (m)
H
Head (m)
n
Free ends n (—)
Q
Discharge (m³/s)

The figure, part by part

Each numbered marker wears the color of its card. Hover a card to light the marker. Tap a marker to jump to that card. The slider walks a red point along the curve; Animate drawing traces it like a pen.

HYD-32 · pipe
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①

Governing law — red

Q=1.84 (L−0.1nH)H3/2Q=1.84\,(L-0.1 n H)H^{3/2}

H∈[0.04,1.2]H \in \left[0.04, 1.2\right]

H=0.04H = 0.04Q=0.022Q = 0.022

②

Domain of the variable — blue

Hmin⁡=0.04,Hmax⁡=1.2H_{\min} = 0.04,\quad H_{\max} = 1.2

H∈[0.04,1.2]H \in \left[0.04, 1.2\right]

H=0.04H = 0.04H=0.04H = 0.04

③

Response curve — green

Q=1.84 (L−0.1nH)H3/2Q=1.84\,(L-0.1 n H)H^{3/2}

H∈[0.04,1.2]H \in \left[0.04, 1.2\right]

H=0.04H = 0.04Q=0.022Q = 0.022

④

Rate of change — amber

dQdH\frac{\mathrm{d}Q}{\mathrm{d}H}

H∈[0.04,1.2]H \in \left[0.04, 1.2\right]

H=0.047H = 0.047Q′=0.89Q^{\prime} = 0.89

Lecture brief

Historical brief

Open-channel and pipe flow were written by Chezy, Manning, Darcy and Weisbach in the nineteenth century, then Bakhmeteff and Bélanger on the hydraulic jump. The sheets compute conveyance, head loss and gradually varied profiles. This sheet (HYD-32 — Francis contracted weir) is the form associated with Francis. Working symbols: LL, HH, nn →\rightarrow QQ. Francis shortened the effective crest by 0.1 H per unsuppressed end. Full-width (n = 0) recovers a simple weir.

Purpose

Purpose: compute QQ from LL, HH, nn in Hydraulics via Q=1.84 (L−0.1nH)H3/2Q=1.84\,(L-0.1 n H)H^{3/2} Q = 1.84 (L − 0.1 n H) H^{3/2} (SI). End contractions n = 0, 1 or 2. Use it when a real hydraulics question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given L=1.500 mL = 1.500\,\mathrm{m}, H=0.300 mH = 0.300\,\mathrm{m}, n=2.000 —n = 2.000\,\mathrm{—}, the governing relation Q=1.84 (L−0.1nH)H3/2Q=1.84\,(L-0.1 n H)H^{3/2} yields Q=0.4354 m3/sQ = 0.4354\,\mathrm{m^{3}/s}. A contracted nappe, a shortened L, a discharge. Move a slider: the numbers are this situation, not a canned story.

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Inputs

Outputs

  • Discharge Q0.4354 m³/s
Reading speed

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HYD-32 · pipe
00:0 / 00:08

Narration of this film

A contracted nappe, a shortened L, a discharge.

Francis shortened the effective crest by 0.1 H per unsuppressed end. Full-width (n = 0) recovers a simple weir.

Reading speed

Watch on YouTube