INGENIA

HYD-33

Culvert inlet-control orifice

Q = Cd A √(2 g (H − y/2)). Inlet-control orifice when the barrel is unsubmerged at the outlet.

Reading speed
CulvertsFHWA inlet control

Governing equation

Q=CdA2g(Hy/2)Q=C_d A\sqrt{2g(H-y/2)}

where

C_d
Inlet Cd ()
A
Barrel area ()
H
Inlet head (m)
y
Inlet depth (m)
Q
Discharge (m³/s)

Lecture brief

Historical brief

Open-channel and pipe flow were written by Chezy, Manning, Darcy and Weisbach in the nineteenth century, then Bakhmeteff and Bélanger on the hydraulic jump. The sheets compute conveyance, head loss and gradually varied profiles. This sheet (HYD-33 — Culvert inlet-control orifice) is the form associated with FHWA inlet control. Working symbols: CdC_d, AA, HH, yy \rightarrow QQ. FHWA inlet-control: the barrel can carry more than the inlet will admit. Head H is measured from the invert.

Purpose

Purpose: compute QQ from CdC_d, AA, HH, yy in Hydraulics via Q=CdA2g(Hy/2)Q=C_d A\sqrt{2g(H-y/2)} Q = Cd A √(2 g (H − y/2)). Inlet-control orifice when the barrel is unsubmerged at the outlet. Use it when a real hydraulics question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given Cd=0.620C_d = 0.620\,\mathrm{—}, A=0.800m2A = 0.800\,\mathrm{m^{2}}, H=1.400mH = 1.400\,\mathrm{m}, y=0.800my = 0.800\,\mathrm{m}, the governing relation Q=CdA2g(Hy/2)Q=C_d A\sqrt{2g(H-y/2)} yields Q=2.197m3/sQ = 2.197\,\mathrm{m^{3}/s}. A pipe through an embankment, an inlet head, a Q. Move a slider: the numbers are this situation, not a canned story.

Calculator

Inputs

Outputs

  • Discharge Q2.197 m³/s
Reading speed

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HYD-33 · pipe
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Narration of this film

A pipe through an embankment, an inlet head, a Q.

FHWA inlet-control: the barrel can carry more than the inlet will admit. Head H is measured from the invert.

Reading speed

Watch on YouTube