INGENIA

GEO-38

Rankine tension-crack depth

zc = 2c /(γ √Ka). Active pressure is zero down to zc; a crack may open.

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Earth pressureRankine tension crack

Governing equation

zc=2cγKaz_c=\dfrac{2c}{\gamma\sqrt{K_a}}

c′∈[1,60]c' \in \left[1, 60\right]

where

c'
Cohesion (kPa)
\gamma
Unit weight (kN/m³)
K_a
Active Ka (—)
z_c
Crack depth (m)

The figure, part by part

Each numbered marker wears the color of its card. Hover a card to light the marker. Tap a marker to jump to that card. The slider walks a red point along the curve; Animate drawing traces it like a pen.

GEO-38 · bearing
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①

Governing law — red

zc=2cγKaz_c=\dfrac{2c}{\gamma\sqrt{K_a}}

c′∈[1,60]c' \in \left[1, 60\right]

c′=1c' = 1zc=0.193z_c = 0.193

②

Domain of the variable — blue

cmin⁡′=1,cmax⁡′=60c'_{\min} = 1,\quad c'_{\max} = 60

c′∈[1,60]c' \in \left[1, 60\right]

c′=1c' = 1c′=1c' = 1

③

Response curve — green

zc=2cγKaz_c=\dfrac{2c}{\gamma\sqrt{K_a}}

c′∈[1,60]c' \in \left[1, 60\right]

c′=1c' = 1zc=0.193z_c = 0.193

④

Rate of change — amber

dzcdc′\frac{\mathrm{d}z_c}{\mathrm{d}c'}

c′∈[1,60]c' \in \left[1, 60\right]

c′=1.371c' = 1.371zc′=0.193z_c^{\prime} = 0.193

Lecture brief

Historical brief

Soil mechanics became a quantitative laboratory after Karl von Terzaghi’s 1925–1943 work on effective stress, consolidation and bearing. These sheets still size shallow foundations, retaining walls, piles and drainage in SI. This sheet (GEO-38 — Rankine tension-crack depth) is the form associated with Rankine tension crack. Working symbols: c′c', γ\gamma, KaK_a →\rightarrow zcz_c. σ′a = Ka σ′v − 2c √Ka vanishes at zc. For φu = 0, Ka = 1 and zc = 2c/γ.

Purpose

Purpose: compute zcz_c from c′c', γ\gamma, KaK_a in Geotechnical engineering via zc=2cγKaz_c=\dfrac{2c}{\gamma\sqrt{K_a}} zc = 2c /(γ √Ka). Active pressure is zero down to zc; a crack may open. Use it when a real geotechnical engineering question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given c′=15.000 kPac' = 15.000\,\mathrm{kPa}, γ=18.000 kN/m3\gamma = 18.000\,\mathrm{kN/m^{3}}, Ka=0.330 —K_a = 0.330\,\mathrm{—}, the governing relation zc=2cγKaz_c=\dfrac{2c}{\gamma\sqrt{K_a}} yields zc=2.90 mz_c = 2.90\,\mathrm{m}. A wall, a dry crack, a shortened thrust diagram. Move a slider: the numbers are this situation, not a canned story.

Calculator

Inputs

Outputs

  • Crack depth z_c2.90 m
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GEO-38 · bearing
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Narration of this film

A wall, a dry crack, a shortened thrust diagram.

σ′a = Ka σ′v − 2c √Ka vanishes at zc. For φu = 0, Ka = 1 and zc = 2c/γ.

Reading speed

Watch on YouTube