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ENV-30

Langmuir isotherm

qe = qmax b Ce /(1 + b Ce). Monolayer on uniform sites.

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AdsorptionLangmuir 1918

Governing equation

qe=qmaxbCe1+bCeq_e=q_{\max}\dfrac{b C_e}{1+b C_e}

where

q_{\max}
Monolayer capacity (mg/g)
b
Affinity b (L/mg)
C_e
Equilibrium conc. (mg/L)
q_e
Solid loading (mg/g)
\theta
Coverage ()

Lecture brief

Historical brief

Streeter–Phelps (1925) oxygen sag, settling theory and Guldberg–Waage kinetics made water and air quality a rate problem. The lab computes sag, overflow and a snapshot of reactor mass balance. This sheet (ENV-30 — Langmuir isotherm) is the form associated with Langmuir 1918. Working symbols: qmaxq_{\max}, bb, CeC_e \rightarrow qeq_e, θ\theta. Langmuir balanced adsorption and desorption rates on a finite number of identical sites, giving a hyperbolic isotherm.

Purpose

Purpose: compute qeq_e, θ\theta from qmaxq_{\max}, bb, CeC_e in Environmental via qe=qmaxbCe1+bCeq_e=q_{\max}\dfrac{b C_e}{1+b C_e} qe = qmax b Ce /(1 + b Ce). Monolayer on uniform sites. Use it when a real environmental question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given qmax=40.000mg/gq_{\max} = 40.000\,\mathrm{mg/g}, b=0.400L/mgb = 0.400\,\mathrm{L/mg}, Ce=5.000mg/LC_e = 5.000\,\mathrm{mg/L}, the governing relation qe=qmaxbCe1+bCeq_e=q_{\max}\dfrac{b C_e}{1+b C_e} yields qe=26.667mg/gq_e = 26.667\,\mathrm{mg/g}, θ=0.667\theta = 0.667\,\mathrm{—}. A surface of sites, a filling fraction θ. Move a slider: the numbers are this situation, not a canned story.

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Inputs

Outputs

  • Solid loading q_e26.667 mg/g
  • Coverage \theta0.667
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ENV-30 · curve
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Narration of this film

A surface of sites, a filling fraction θ.

Langmuir balanced adsorption and desorption rates on a finite number of identical sites, giving a hyperbolic isotherm.

Reading speed

Watch on YouTube