INGENIA

ELC-23

Skin depth

δ = √(2ρ / ωμ) = √(ρ / π f μ). AC current hugs the surface.

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FieldsKelvin

Governing equation

δ=2ρωμ=ρπfμ\delta=\sqrt{\dfrac{2\rho}{\omega\mu}}=\sqrt{\dfrac{\rho}{\pi f\mu}}

where

\rho
Resistivity (nΩ·m)
f
Frequency (Hz)
\mu_r
Relative μ ()
\delta
Skin depth (mm)

Lecture brief

Historical brief

Ohm (1827), Kirchhoff (1845) and Maxwell’s circuit reduction still run every board: RLC transients, transformers, skin effect and three-phase power. The sheets are those network laws, not a SPICE deck. This sheet (ELC-23 — Skin depth) is the form associated with Kelvin. Working symbols: ρ\rho, ff, μr\mu_r \rightarrow δ\delta. Eddy currents cancel the field in the bulk, leaving an exponential skin of thickness δ.

Purpose

Purpose: compute δ\delta from ρ\rho, ff, μr\mu_r in Electrical via δ=2ρωμ=ρπfμ\delta=\sqrt{\dfrac{2\rho}{\omega\mu}}=\sqrt{\dfrac{\rho}{\pi f\mu}} δ = √(2ρ / ωμ) = √(ρ / π f μ). AC current hugs the surface. Use it when a real electrical question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given ρ=17.000nΩm\rho = 17.000\,\mathrm{nΩ·m}, f=50.000Hzf = 50.000\,\mathrm{Hz}, μr=1.000\mu_r = 1.000\,\mathrm{—}, the governing relation δ=2ρωμ=ρπfμ\delta=\sqrt{\dfrac{2\rho}{\omega\mu}}=\sqrt{\dfrac{\rho}{\pi f\mu}} yields δ=9.2802mm\delta = 9.2802\,\mathrm{mm}. A round wire, a current annulus, a δ ring. Move a slider: the numbers are this situation, not a canned story.

Calculator

Inputs

Outputs

  • Skin depth \delta9.2802 mm
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ELC-23 · wave
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Narration of this film

A round wire, a current annulus, a δ ring.

Eddy currents cancel the field in the bulk, leaving an exponential skin of thickness δ.

Reading speed

Watch on YouTube