INGENIA

CHM-26

Second-order 1/c law

1/c = 1/c0 + k t. Remaining concentration of a 2A → products step.

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KineticsSecond-order kinetics

Governing equation

1c=1c0+kt\dfrac1c=\dfrac1{c_0}+kt

where

c_0
Initial concentration (mol/L)
k
Rate constant (L/(mol·s))
t
Time (s)
c
Remaining c (mol/L)
1/c
Reciprocal c (L/mol)

Lecture brief

Historical brief

Ideal-gas law, van ’t Hoff, Nernst, Michaelis–Menten and Clausius–Clapeyron are physical chemistry’s working equations of equilibrium and rate. The lab is pressure, potential and kinetics. This sheet (CHM-26 — Second-order 1/c law) is the form associated with Second-order kinetics. Working symbols: c0c_0, kk, tt \rightarrow cc, 1/c1/c. Integrate dc/dt = −k c². A plot of 1/c vs t is linear with slope k.

Purpose

Purpose: compute cc, 1/c1/c from c0c_0, kk, tt in Physical chemistry via 1c=1c0+kt\dfrac1c=\dfrac1{c_0}+kt 1/c = 1/c0 + k t. Remaining concentration of a 2A → products step. Use it when a real physical chemistry question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given c0=0.500mol/Lc_0 = 0.500\,\mathrm{mol/L}, k=0.020L/(mols)k = 0.020\,\mathrm{L/(mol·s)}, t=30.000st = 30.000\,\mathrm{s}, the governing relation 1c=1c0+kt\dfrac1c=\dfrac1{c_0}+kt yields c=0.3846mol/Lc = 0.3846\,\mathrm{mol/L}, 1/c=2.6000L/mol1/c = 2.6000\,\mathrm{L/mol}. Equal-concentration second order, constant volume. Move a slider: the numbers are this situation, not a canned story.

Calculator

Inputs

Outputs

  • Remaining c c0.3846 mol/L
  • Reciprocal c 1/c2.6000 L/mol
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CHM-26 · decay
00:0 / 00:08

Narration of this film

Equal-concentration second order, constant volume.

Integrate dc/dt = −k c². A plot of 1/c vs t is linear with slope k.

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Watch on YouTube