INGENIA

CHM-26

Second-order 1/c law

1/c = 1/c0 + k t. Remaining concentration of a 2A → products step.

Reading speed
KineticsSecond-order kinetics

Governing equation

1c=1c0+kt\dfrac1c=\dfrac1{c_0}+kt

t∈[0,500]t \in \left[0, 500\right]

where

c_0
Initial concentration (mol/L)
k
Rate constant (L/(mol·s))
t
Time (s)
c
Remaining c (mol/L)
1/c
Reciprocal c (L/mol)

The figure, part by part

Each numbered marker wears the color of its card. Hover a card to light the marker. Tap a marker to jump to that card. The slider walks a red point along the curve; Animate drawing traces it like a pen.

CHM-26 · decay
00:0 / 00:08
①

Governing law — red

1c=1c0+kt\dfrac1c=\dfrac1{c_0}+kt

t∈[0,500]t \in \left[0, 500\right]

t=0t = 0c=0.5c = 0.5

②

Domain of the variable — blue

tmin⁡=0,tmax⁡=500t_{\min} = 0,\quad t_{\max} = 500

t∈[0,500]t \in \left[0, 500\right]

t=0t = 0t=0t = 0

③

Response curve — green

1c=1c0+kt\dfrac1c=\dfrac1{c_0}+kt

t∈[0,500]t \in \left[0, 500\right]

t=0t = 0c=0.5c = 0.5

④

Rate of change — amber

dcdt\frac{\mathrm{d}c}{\mathrm{d}t}

t∈[0,500]t \in \left[0, 500\right]

t=3.145t = 3.145c′=−0.005c^{\prime} = -0.005

Lecture brief

Historical brief

Ideal-gas law, van ’t Hoff, Nernst, Michaelis–Menten and Clausius–Clapeyron are physical chemistry’s working equations of equilibrium and rate. The lab is pressure, potential and kinetics. This sheet (CHM-26 — Second-order 1/c law) is the form associated with Second-order kinetics. Working symbols: c0c_0, kk, tt →\rightarrow cc, 1/c1/c. Integrate dc/dt = −k c². A plot of 1/c vs t is linear with slope k.

Purpose

Purpose: compute cc, 1/c1/c from c0c_0, kk, tt in Physical chemistry via 1c=1c0+kt\dfrac1c=\dfrac1{c_0}+kt 1/c = 1/c0 + k t. Remaining concentration of a 2A → products step. Use it when a real physical chemistry question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given c0=0.500 mol/Lc_0 = 0.500\,\mathrm{mol/L}, k=0.020 L/(mol⋅s)k = 0.020\,\mathrm{L/(mol·s)}, t=30.000 st = 30.000\,\mathrm{s}, the governing relation 1c=1c0+kt\dfrac1c=\dfrac1{c_0}+kt yields c=0.3846 mol/Lc = 0.3846\,\mathrm{mol/L}, 1/c=2.6000 L/mol1/c = 2.6000\,\mathrm{L/mol}. Equal-concentration second order, constant volume. Move a slider: the numbers are this situation, not a canned story.

Calculator

Inputs

Outputs

  • Remaining c c0.3846 mol/L
  • Reciprocal c 1/c2.6000 L/mol
Reading speed

Watch on YouTube

Free library

Full library

Free PDF / open book

YouTube channels

CHM-26 · decay
00:0 / 00:08

Narration of this film

Equal-concentration second order, constant volume.

Integrate dc/dt = −k c². A plot of 1/c vs t is linear with slope k.

Reading speed

Watch on YouTube