INGENIA

CHE-04

Fenske minimum stages

Nmin = ln[(xD/(1−xD))((1−xB)/xB)] / ln α.

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DistillationFenske 1932McCabe–Thiele

Governing equation

Nmin=ln[xD1xD1xBxB]lnαN_{\min}=\dfrac{\ln\left[\dfrac{x_D}{1-x_D}\dfrac{1-x_B}{x_B}\right]}{\ln\alpha}

where

x_D
Distillate mole frac. ()
x_B
Bottoms mole frac. ()
\alpha
Relative volatility ()
N_{\min}
Minimum stages ()

Lecture brief

Historical brief

From CSTR/PFR mole balances and Arrhenius rates to McCabe–Thiele stages and NTU exchangers, chemical engineering is conservation plus equilibrium. The lab is that design arithmetic. This sheet (CHE-04 — Fenske minimum stages) is the form associated with Fenske 1932 · McCabe–Thiele. Working symbols: xDx_D, xBx_B, α\alpha \rightarrow NminN_{\min}. At total reflux McCabe–Thiele steps collapse to the Fenske logarithm of the relative volatility, the minimum number of equilibrium stages.

Purpose

Purpose: compute NminN_{\min} from xDx_D, xBx_B, α\alpha in Chemical engineering via Nmin=ln[xD1xD1xBxB]lnαN_{\min}=\dfrac{\ln\left[\dfrac{x_D}{1-x_D}\dfrac{1-x_B}{x_B}\right]}{\ln\alpha} Nmin = ln[(xD/(1−xD))((1−xB)/xB)] / ln α. Use it when a real chemical engineering question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given xD=0.950x_D = 0.950\,\mathrm{—}, xB=0.050x_B = 0.050\,\mathrm{—}, α=2.200\alpha = 2.200\,\mathrm{—}, the governing relation Nmin=ln[xD1xD1xBxB]lnαN_{\min}=\dfrac{\ln\left[\dfrac{x_D}{1-x_D}\dfrac{1-x_B}{x_B}\right]}{\ln\alpha} yields Nmin=7.469N_{\min} = 7.469\,\mathrm{—}. Binary, constant α, total reflux. Move a slider: the numbers are this situation, not a canned story.

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Outputs

  • Minimum stages N_{\min}7.469
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Narration of this film

Binary, constant α, total reflux.

At total reflux McCabe–Thiele steps collapse to the Fenske logarithm of the relative volatility, the minimum number of equilibrium stages.

Reading speed

Watch on YouTube