INGENIA

CHE-24

Counterflow NTU effectiveness

ε = (1−e^{−NTU(1−Cr)})/(1−Cr e^{−NTU(1−Cr)}).

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Heat exchangersKays–London

Governing equation

ε=1−e−NTU(1−Cr)1−Cre−NTU(1−Cr)\varepsilon=\dfrac{1-e^{-\mathrm{NTU}(1-C_r)}}{1-C_r e^{-\mathrm{NTU}(1-C_r)}}

NTU∈[0.1,8]NTU \in \left[0.1, 8\right]

where

NTU
Number of transfer units (—)
C_r
Capacity ratio (—)
\varepsilon
Effectiveness (—)

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①

Governing law — red

ε=1−e−NTU(1−Cr)1−Cre−NTU(1−Cr)\varepsilon=\dfrac{1-e^{-\mathrm{NTU}(1-C_r)}}{1-C_r e^{-\mathrm{NTU}(1-C_r)}}

NTU∈[0.1,8]NTU \in \left[0.1, 8\right]

NTU=0.1NTU = 0.1ε=0.093\varepsilon = 0.093

②

Domain of the variable — blue

NTUmin⁡=0.1,NTUmax⁡=8NTU_{\min} = 0.1,\quad NTU_{\max} = 8

NTU∈[0.1,8]NTU \in \left[0.1, 8\right]

NTU=0.1NTU = 0.1NTU=0.1NTU = 0.1

③

Response curve — green

ε=1−e−NTU(1−Cr)1−Cre−NTU(1−Cr)\varepsilon=\dfrac{1-e^{-\mathrm{NTU}(1-C_r)}}{1-C_r e^{-\mathrm{NTU}(1-C_r)}}

NTU∈[0.1,8]NTU \in \left[0.1, 8\right]

NTU=0.1NTU = 0.1ε=0.093\varepsilon = 0.093

④

Rate of change — amber

dεdNTU\frac{\mathrm{d}\varepsilon}{\mathrm{d}NTU}

NTU∈[0.1,8]NTU \in \left[0.1, 8\right]

NTU=0.15NTU = 0.15ε′=0.808\varepsilon^{\prime} = 0.808

Lecture brief

Historical brief

From CSTR/PFR mole balances and Arrhenius rates to McCabe–Thiele stages and NTU exchangers, chemical engineering is conservation plus equilibrium. The lab is that design arithmetic. This sheet (CHE-24 — Counterflow NTU effectiveness) is the form associated with Kays–London. Working symbols: NTUNTU, CrC_r →\rightarrow ε\varepsilon. The ε–NTU method integrates the local energy balance of a counterflow exchanger, with Cr = Cmin/Cmax.

Purpose

Purpose: compute ε\varepsilon from NTUNTU, CrC_r in Chemical engineering via ε=1−e−NTU(1−Cr)1−Cre−NTU(1−Cr)\varepsilon=\dfrac{1-e^{-\mathrm{NTU}(1-C_r)}}{1-C_r e^{-\mathrm{NTU}(1-C_r)}} ε = (1−e^{−NTU(1−Cr)})/(1−Cr e^{−NTU(1−Cr)}). Use it when a real chemical engineering question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given NTU=2.000 —NTU = 2.000\,\mathrm{—}, Cr=0.500 —C_r = 0.500\,\mathrm{—}, the governing relation ε=1−e−NTU(1−Cr)1−Cre−NTU(1−Cr)\varepsilon=\dfrac{1-e^{-\mathrm{NTU}(1-C_r)}}{1-C_r e^{-\mathrm{NTU}(1-C_r)}} yields ε=0.7746 —\varepsilon = 0.7746\,\mathrm{—}. Two streams, an NTU bar, an ε tick. Move a slider: the numbers are this situation, not a canned story.

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Outputs

  • Effectiveness \varepsilon0.7746 —
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Narration of this film

Two streams, an NTU bar, an ε tick.

The ε–NTU method integrates the local energy balance of a counterflow exchanger, with Cr = Cmin/Cmax.

Reading speed

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