INGENIA

THM-03

Clausius entropy (reversible heat)

ΔS = Qrev / T for a reservoir exchange.

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EntropyClausius 1865

Governing equation

ΔS=QrevT\Delta S = \dfrac{Q_{\mathrm{rev}}}{T}

T∈[50,2000]T \in \left[50, 2000\right]

where

Q_{\mathrm{rev}}
Reversible heat (kJ)
T
Temperature (K)
\Delta S
Entropy change (kJ/K)

The figure, part by part

Each numbered marker wears the color of its card. Hover a card to light the marker. Tap a marker to jump to that card. The slider walks a red point along the curve; Animate drawing traces it like a pen.

THM-03 · phase
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①

Governing law — red

ΔS=QrevT\Delta S = \dfrac{Q_{\mathrm{rev}}}{T}

T∈[50,2000]T \in \left[50, 2000\right]

T=50T = 50ΔS=0.4\Delta S = 0.4

②

Domain of the variable — blue

Tmin⁡=50,Tmax⁡=2000T_{\min} = 50,\quad T_{\max} = 2000

T∈[50,2000]T \in \left[50, 2000\right]

T=50T = 50T=50T = 50

③

Response curve — green

ΔS=QrevT\Delta S = \dfrac{Q_{\mathrm{rev}}}{T}

T∈[50,2000]T \in \left[50, 2000\right]

T=50T = 50ΔS=0.4\Delta S = 0.4

④

Rate of change — amber

dΔSdT\frac{\mathrm{d}\Delta S}{\mathrm{d}T}

T∈[50,2000]T \in \left[50, 2000\right]

T=62.26T = 62.26ΔS′=−0.005\Delta S^{\prime} = -0.005

Lecture brief

Historical brief

Carnot (1824), Clausius entropy, the first law and later van der Waals and Gibbs potentials turned heat into a state science. The sheets compute work, efficiency and vapour pressure. This sheet (THM-03 — Clausius entropy (reversible heat)) is the form associated with Clausius 1865. Working symbols: QrevQ_{\mathrm{rev}}, TT →\rightarrow ΔS\Delta S. Clausius defined dS = đQrev / T so that ∮ đQ/T ≤ 0, with equality for reversible cycles.

Purpose

Purpose: compute ΔS\Delta S from QrevQ_{\mathrm{rev}}, TT in Thermodynamics via ΔS=QrevT\Delta S = \dfrac{Q_{\mathrm{rev}}}{T} ΔS = Qrev / T for a reservoir exchange. Use it when a real thermodynamics question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given Qrev=20.000 kJQ_{\mathrm{rev}} = 20.000\,\mathrm{kJ}, T=300.000 KT = 300.000\,\mathrm{K}, the governing relation ΔS=QrevT\Delta S = \dfrac{Q_{\mathrm{rev}}}{T} yields ΔS=0.0667 kJ/K\Delta S = 0.0667\,\mathrm{kJ/K}. Isothermal reversible transfer with a single T. Move a slider: the numbers are this situation, not a canned story.

Calculator

Inputs

Outputs

  • Entropy change \Delta S0.0667 kJ/K
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THM-03 · phase
00:0 / 00:08

Narration of this film

Isothermal reversible transfer with a single T.

Clausius defined dS = đQrev / T so that ∮ đQ/T ≤ 0, with equality for reversible cycles.

Reading speed

Watch on YouTube