INGENIA

RPR-16

Lead thickness from TVL

x = TVL log10(1/B). Lead (or concrete) needed for transmission B.

Reading speed
ShieldingLead thickness

Governing equation

x=TVL log⁡10(1/B)x=\mathrm{TVL}\,\log_{10}(1/B)

B∈[1×10−6,0.5]B \in \left[1\times 10^{-6}, 0.5\right]

where

TVL
Tenth-value layer (mm)
B
Required transmission (—)
x
Shield thickness (mm)
n
Number of TVLs (—)

The figure, part by part

Each numbered marker wears the color of its card. Hover a card to light the marker. Tap a marker to jump to that card. The slider walks a red point along the curve; Animate drawing traces it like a pen.

RPR-16 · gauge
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①

Governing law — red

x=TVL log⁡10(1/B)x=\mathrm{TVL}\,\log_{10}(1/B)

B∈[1×10−6,0.5]B \in \left[1\times 10^{-6}, 0.5\right]

B=1×10−6B = 1\times 10^{-6}x=72x = 72

②

Domain of the variable — blue

Bmin⁡=1×10−6,Bmax⁡=0.5B_{\min} = 1\times 10^{-6},\quad B_{\max} = 0.5

B∈[1×10−6,0.5]B \in \left[1\times 10^{-6}, 0.5\right]

B=1×10−6B = 1\times 10^{-6}B=1×10−6B = 1\times 10^{-6}

③

Response curve — green

x=TVL log⁡10(1/B)x=\mathrm{TVL}\,\log_{10}(1/B)

B∈[1×10−6,0.5]B \in \left[1\times 10^{-6}, 0.5\right]

B=1×10−6B = 1\times 10^{-6}x=72x = 72

④

Rate of change — amber

dxdB\frac{\mathrm{d}x}{\mathrm{d}B}

B∈[1×10−6,0.5]B \in \left[1\times 10^{-6}, 0.5\right]

B=0.003B = 0.003x′=−7247.9x^{\prime} = -7247.9

Lecture brief

Historical brief

Inverse-square, half-value layer, ICRP weighting and ALARA are the protection craft since the 1920s commissions. The lab computes transmission, equivalent dose and a shielding snapshot. This sheet (RPR-16 — Lead thickness from TVL) is the form associated with Lead thickness. Working symbols: TVLTVL, BB →\rightarrow xx, nn. First TVL is larger than equilibrium TVL. Diagnostic lead: ~0.3–0.5 mm HVL at 80 kV; linac concrete: tens of cm.

Purpose

Purpose: compute xx, nn from TVLTVL, BB in Radiation protection via x=TVL log⁡10(1/B)x=\mathrm{TVL}\,\log_{10}(1/B) x = TVL log10(1/B). Lead (or concrete) needed for transmission B. Use it when a real radiation protection question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given TVL=12.000 mmTVL = 12.000\,\mathrm{mm}, B=0.010 —B = 0.010\,\mathrm{—}, the governing relation x=TVL log⁡10(1/B)x=\mathrm{TVL}\,\log_{10}(1/B) yields x=24.00 mmx = 24.00\,\mathrm{mm}, n=2.00 —n = 2.00\,\mathrm{—}. A required B and a stack of tenth-value sheets. Move a slider: the numbers are this situation, not a canned story.

Calculator

Inputs

Outputs

  • Shield thickness x24.00 mm
  • Number of TVLs n2.00 —
Reading speed

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RPR-16 · gauge
00:0 / 00:08

Narration of this film

A required B and a stack of tenth-value sheets.

First TVL is larger than equilibrium TVL. Diagnostic lead: ~0.3–0.5 mm HVL at 80 kV; linac concrete: tens of cm.

Reading speed

Watch on YouTube