INGENIA

RPR-25

Exclusion-zone radius

r = r0 √(Ḣ0 / Ḣ_lim). Inverse-square radius of a dose-rate contour.

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ZoningExclusion radius

Governing equation

r=r0H˙0/H˙lim⁡r=r_0\sqrt{\dot H_0/\dot H_{\lim}}

H˙lim∈[0.05,25]\dot H_{lim} \in \left[0.05, 25\right]

where

\dot H_0
Rate at r0 (µSv/h)
r_0
Reference distance (m)
\dot H_{lim}
Contour limit (µSv/h)
r
Exclusion radius (m)

The figure, part by part

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RPR-25 · dose
00:0 / 00:08
①

Governing law — red

r=r0H˙0/H˙lim⁡r=r_0\sqrt{\dot H_0/\dot H_{\lim}}

H˙lim∈[0.05,25]\dot H_{lim} \in \left[0.05, 25\right]

H˙lim=0.05\dot H_{lim} = 0.05r=40r = 40

②

Domain of the variable — blue

\dot H_{lim}_{\min} = 0.05,\quad \dot H_{lim}_{\max} = 25

H˙lim∈[0.05,25]\dot H_{lim} \in \left[0.05, 25\right]

H˙lim=0.05\dot H_{lim} = 0.05H˙lim=0.05\dot H_{lim} = 0.05

③

Response curve — green

r=r0H˙0/H˙lim⁡r=r_0\sqrt{\dot H_0/\dot H_{\lim}}

H˙lim∈[0.05,25]\dot H_{lim} \in \left[0.05, 25\right]

H˙lim=0.05\dot H_{lim} = 0.05r=40r = 40

④

Rate of change — amber

drdH˙lim\frac{\mathrm{d}r}{\mathrm{d}\dot H_{lim}}

H˙lim∈[0.05,25]\dot H_{lim} \in \left[0.05, 25\right]

H˙lim=0.207\dot H_{lim} = 0.207r′=−80.21r^{\prime} = -80.21

Lecture brief

Historical brief

Inverse-square, half-value layer, ICRP weighting and ALARA are the protection craft since the 1920s commissions. The lab computes transmission, equivalent dose and a shielding snapshot. This sheet (RPR-25 — Exclusion-zone radius) is the form associated with Exclusion radius. Working symbols: H˙0\dot H_0, r0r_0, H˙lim\dot H_{lim} →\rightarrow rr. Public 0.5 µSv/h and controlled 7.5 µSv/h are common contour values (≈1 mSv/y public at 2000 h). Scatter and shielding shrink the true radius.

Purpose

Purpose: compute rr from H˙0\dot H_0, r0r_0, H˙lim\dot H_{lim} in Radiation protection via r=r0H˙0/H˙lim⁡r=r_0\sqrt{\dot H_0/\dot H_{\lim}} r = r0 √(Ḣ0 / Ḣ_lim). Inverse-square radius of a dose-rate contour. Use it when a real radiation protection question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given H˙0=80.000 μSv/h\dot H_0 = 80.000\,\mathrm{\mu Sv/h}, r0=1.000 mr_0 = 1.000\,\mathrm{m}, H˙lim=0.500 μSv/h\dot H_{lim} = 0.500\,\mathrm{\mu Sv/h}, the governing relation r=r0H˙0/H˙lim⁡r=r_0\sqrt{\dot H_0/\dot H_{\lim}} yields r=12.65 mr = 12.65\,\mathrm{m}. A source and a circular keep-out painted on the floor. Move a slider: the numbers are this situation, not a canned story.

Calculator

Inputs

Outputs

  • Exclusion radius r12.65 m
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RPR-25 · dose
00:0 / 00:08

Narration of this film

A source and a circular keep-out painted on the floor.

Public 0.5 µSv/h and controlled 7.5 µSv/h are common contour values (≈1 mSv/y public at 2000 h). Scatter and shielding shrink the true radius.

Reading speed

Watch on YouTube