INGENIA

RTH-22

Wedge angle

θ = arctan((z_toe − z_heel)/x). Tilt of an isodose between toe and heel.

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WedgesICRU wedge angle

Governing equation

θ=arctan⁡ ⁣((ztoe−zheel)/x)\theta=\arctan\!\left((z_{\mathrm{toe}}-z_{\mathrm{heel}})/x\right)

ztoe∈[2,25]z_{toe} \in \left[2, 25\right]

where

z_{toe}
Toe isodose depth (cm)
z_{heel}
Heel isodose depth (cm)
x
Separation (cm)
\theta
Wedge angle (°)

The figure, part by part

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RTH-22 · gauge
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①

Governing law — red

θ=arctan⁡ ⁣((ztoe−zheel)/x)\theta=\arctan\!\left((z_{\mathrm{toe}}-z_{\mathrm{heel}})/x\right)

ztoe∈[2,25]z_{toe} \in \left[2, 25\right]

ztoe=2z_{toe} = 2θ=−30.96\theta = -30.96

②

Domain of the variable — blue

z_{toe}_{\min} = 2,\quad z_{toe}_{\max} = 25

ztoe∈[2,25]z_{toe} \in \left[2, 25\right]

ztoe=2z_{toe} = 2ztoe=2z_{toe} = 2

③

Response curve — green

θ=arctan⁡ ⁣((ztoe−zheel)/x)\theta=\arctan\!\left((z_{\mathrm{toe}}-z_{\mathrm{heel}})/x\right)

ztoe∈[2,25]z_{toe} \in \left[2, 25\right]

ztoe=2z_{toe} = 2θ=−30.96\theta = -30.96

④

Rate of change — amber

dθdztoe\frac{\mathrm{d}\theta}{\mathrm{d}z_{toe}}

ztoe∈[2,25]z_{toe} \in \left[2, 25\right]

ztoe=2.145z_{toe} = 2.145θ′=4.267\theta^{\prime} = 4.267

Lecture brief

Historical brief

The linear-quadratic model, BED, tissue-maximum ratio and Clarkson scatter turned radiotherapy into fraction arithmetic. MU calculation on these sheets is that clinical closed form. This sheet (RTH-22 — Wedge angle) is the form associated with ICRU wedge angle. Working symbols: ztoez_{toe}, zheelz_{heel}, xx →\rightarrow θ\theta. ICRU quotes the angle between the 50 % isodose (often at 10 cm) and the normal to CAX.

Purpose

Purpose: compute θ\theta from ztoez_{toe}, zheelz_{heel}, xx in Radiotherapy via θ=arctan⁡ ⁣((ztoe−zheel)/x)\theta=\arctan\!\left((z_{\mathrm{toe}}-z_{\mathrm{heel}})/x\right) θ = arctan((z_toe − z_heel)/x). Tilt of an isodose between toe and heel. Use it when a real radiotherapy question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given ztoe=12.000 cmz_{toe} = 12.000\,\mathrm{cm}, zheel=8.000 cmz_{heel} = 8.000\,\mathrm{cm}, x=10.000 cmx = 10.000\,\mathrm{cm}, the governing relation θ=arctan⁡ ⁣((ztoe−zheel)/x)\theta=\arctan\!\left((z_{\mathrm{toe}}-z_{\mathrm{heel}})/x\right) yields θ=21.8 ∘\theta = 21.8\,\mathrm{^{\circ}}. A tilted isodose across a wedged field. Move a slider: the numbers are this situation, not a canned story.

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Inputs

Outputs

  • Wedge angle \theta21.8 °
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RTH-22 · gauge
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Narration of this film

A tilted isodose across a wedged field.

ICRU quotes the angle between the 50 % isodose (often at 10 cm) and the normal to CAX.

Reading speed

Watch on YouTube