INGENIA

RTH-09

Mayneord F-factor

F = [((SSD2+dm)/(SSD1+dm)) ((SSD1+d)/(SSD2+d))]². Converts PDD between SSDs.

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Beam dataMayneord

Governing equation

F=(SSD2+dmSSD1+dmSSD1+dSSD2+d)2F=\left(\dfrac{\mathrm{SSD}_2+d_m}{\mathrm{SSD}_1+d_m}\cdot\dfrac{\mathrm{SSD}_1+d}{\mathrm{SSD}_2+d}\right)^{2}

where

SSD_1
Original SSD (cm)
SSD_2
New SSD (cm)
d
Depth (cm)
d_m
dmax (cm)
F
Mayneord F ()

Lecture brief

Historical brief

The linear-quadratic model, BED, tissue-maximum ratio and Clarkson scatter turned radiotherapy into fraction arithmetic. MU calculation on these sheets is that clinical closed form. This sheet (RTH-09 — Mayneord F-factor) is the form associated with Mayneord. Working symbols: SSD1SSD_1, SSD2SSD_2, dd, dmd_m \rightarrow FF. Pure inverse-square; scatter change with SSD is ignored. Good near dmax, poorer at depth.

Purpose

Purpose: compute FF from SSD1SSD_1, SSD2SSD_2, dd, dmd_m in Radiotherapy via F=(SSD2+dmSSD1+dmSSD1+dSSD2+d)2F=\left(\dfrac{\mathrm{SSD}_2+d_m}{\mathrm{SSD}_1+d_m}\cdot\dfrac{\mathrm{SSD}_1+d}{\mathrm{SSD}_2+d}\right)^{2} F = [((SSD2+dm)/(SSD1+dm)) ((SSD1+d)/(SSD2+d))]². Converts PDD between SSDs. Use it when a real radiotherapy question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given SSD1=100.000cmSSD_1 = 100.000\,\mathrm{cm}, SSD2=120.000cmSSD_2 = 120.000\,\mathrm{cm}, d=10.000cmd = 10.000\,\mathrm{cm}, dm=1.500cmd_m = 1.500\,\mathrm{cm}, the governing relation F=(SSD2+dmSSD1+dmSSD1+dSSD2+d)2F=\left(\dfrac{\mathrm{SSD}_2+d_m}{\mathrm{SSD}_1+d_m}\cdot\dfrac{\mathrm{SSD}_1+d}{\mathrm{SSD}_2+d}\right)^{2} yields F=1.0259F = 1.0259\,\mathrm{—}. Two SSDs, one depth, a conversion factor. Move a slider: the numbers are this situation, not a canned story.

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Inputs

Outputs

  • Mayneord F F1.0259
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RTH-09 · dose
00:0 / 00:08

Narration of this film

Two SSDs, one depth, a conversion factor.

Pure inverse-square; scatter change with SSD is ignored. Good near dmax, poorer at depth.

Reading speed

Watch on YouTube