INGENIA

RTH-30

α/β from two isoeffects

α/β = (n2 d2² − n1 d1²)/(n1 d1 − n2 d2). Two equal-BED schedules.

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RadiobiologyIsoeffect α/β

Governing equation

α/β=n2d22n1d12n1d1n2d2\alpha/\beta=\dfrac{n_2 d_2^2-n_1 d_1^2}{n_1 d_1-n_2 d_2}

where

n_1
Fractions 1 ()
d_1
Dose/fx 1 (Gy)
n_2
Fractions 2 ()
d_2
Dose/fx 2 (Gy)
\alpha/\beta
Recovered α/β (Gy)

Lecture brief

Historical brief

The linear-quadratic model, BED, tissue-maximum ratio and Clarkson scatter turned radiotherapy into fraction arithmetic. MU calculation on these sheets is that clinical closed form. This sheet (RTH-30 — α/β from two isoeffects) is the form associated with Isoeffect α/β. Working symbols: n1n_1, d1d_1, n2n_2, d2d_2 \rightarrow α/β\alpha/\beta. Withers' isoeffect: n1 d1 (1+d1/(α/β)) = n2 d2 (1+d2/(α/β)). Solve for α/β.

Purpose

Purpose: compute α/β\alpha/\beta from n1n_1, d1d_1, n2n_2, d2d_2 in Radiotherapy via α/β=n2d22n1d12n1d1n2d2\alpha/\beta=\dfrac{n_2 d_2^2-n_1 d_1^2}{n_1 d_1-n_2 d_2} α/β = (n2 d2² − n1 d1²)/(n1 d1 − n2 d2). Two equal-BED schedules. Use it when a real radiotherapy question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given n1=30.000n_1 = 30.000\,\mathrm{—}, d1=2.000Gyd_1 = 2.000\,\mathrm{Gy}, n2=5.000n_2 = 5.000\,\mathrm{—}, d2=6.000Gyd_2 = 6.000\,\mathrm{Gy}, the governing relation α/β=n2d22n1d12n1d1n2d2\alpha/\beta=\dfrac{n_2 d_2^2-n_1 d_1^2}{n_1 d_1-n_2 d_2} yields α/β=2.00Gy\alpha/\beta = 2.00\,\mathrm{Gy}. Two fractionation calendars meeting at one BED. Move a slider: the numbers are this situation, not a canned story.

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Outputs

  • Recovered α/β \alpha/\beta2.00 Gy
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RTH-30 · gauge
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Narration of this film

Two fractionation calendars meeting at one BED.

Withers' isoeffect: n1 d1 (1+d1/(α/β)) = n2 d2 (1+d2/(α/β)). Solve for α/β.

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