INGENIA

RAD-04

Bragg–Gray cavity dose

D_med / D_gas = (S/ρ)_med / (S/ρ)_gas. Gas cavity in a medium.

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DosimetryBragg–Gray

Governing equation

Dmed=Dgas(S/ρ)med(S/ρ)gasD_{med}=D_{gas}\dfrac{(S/\rho)_{med}}{(S/\rho)_{gas}}

Dgas∈[0.01,20]D_{gas} \in \left[0.01, 20\right]

where

D_{gas}
Gas dose (Gy)
(S/\rho)_{med}
Medium stopping (MeV cm²/g)
(S/\rho)_{gas}
Gas stopping (MeV cm²/g)
D_{med}
Medium dose (Gy)

The figure, part by part

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RAD-04 · dose
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①

Governing law — red

Dmed=Dgas(S/ρ)med(S/ρ)gasD_{med}=D_{gas}\dfrac{(S/\rho)_{med}}{(S/\rho)_{gas}}

Dgas∈[0.01,20]D_{gas} \in \left[0.01, 20\right]

Dgas=0.01D_{gas} = 0.01Dmed=0.011D_{med} = 0.011

②

Domain of the variable — blue

D_{gas}_{\min} = 0.01,\quad D_{gas}_{\max} = 20

Dgas∈[0.01,20]D_{gas} \in \left[0.01, 20\right]

Dgas=0.01D_{gas} = 0.01Dgas=0.01D_{gas} = 0.01

③

Response curve — green

Dmed=Dgas(S/ρ)med(S/ρ)gasD_{med}=D_{gas}\dfrac{(S/\rho)_{med}}{(S/\rho)_{gas}}

Dgas∈[0.01,20]D_{gas} \in \left[0.01, 20\right]

Dgas=0.01D_{gas} = 0.01Dmed=0.011D_{med} = 0.011

④

Rate of change — amber

dDmeddDgas\frac{\mathrm{d}D_{med}}{\mathrm{d}D_{gas}}

Dgas∈[0.01,20]D_{gas} \in \left[0.01, 20\right]

Dgas=0.136D_{gas} = 0.136Dmed′=1.111D_{med}^{\prime} = 1.111

Lecture brief

Historical brief

Beer attenuation, Compton (1923), Klein–Nishina, Bragg–Gray cavity and KERMA are the transport of photons and charged particles in matter. The sheets compute fluence, kerma and stopping. This sheet (RAD-04 — Bragg–Gray cavity dose) is the form associated with Bragg–Gray. Working symbols: DgasD_{gas}, (S/ρ)med(S/\rho)_{med}, (S/ρ)gas(S/\rho)_{gas} →\rightarrow DmedD_{med}. Requires charged-particle equilibrium across a small cavity. Spencer–Attix refines the cutoff.

Purpose

Purpose: compute DmedD_{med} from DgasD_{gas}, (S/ρ)med(S/\rho)_{med}, (S/ρ)gas(S/\rho)_{gas} in Radiation physics via Dmed=Dgas(S/ρ)med(S/ρ)gasD_{med}=D_{gas}\dfrac{(S/\rho)_{med}}{(S/\rho)_{gas}} D_med / D_gas = (S/ρ)_med / (S/ρ)_gas. Gas cavity in a medium. Use it when a real radiation physics question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given Dgas=1.000 GyD_{gas} = 1.000\,\mathrm{Gy}, (S/ρ)med=2.000 MeVcm2/g(S/\rho)_{med} = 2.000\,\mathrm{MeV cm^{2}/g}, (S/ρ)gas=1.800 MeVcm2/g(S/\rho)_{gas} = 1.800\,\mathrm{MeV cm^{2}/g}, the governing relation Dmed=Dgas(S/ρ)med(S/ρ)gasD_{med}=D_{gas}\dfrac{(S/\rho)_{med}}{(S/\rho)_{gas}} yields Dmed=1.111 GyD_{med} = 1.111\,\mathrm{Gy}. A phantom, a tiny air cavity, two doses. Move a slider: the numbers are this situation, not a canned story.

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Inputs

Outputs

  • Medium dose D_{med}1.111 Gy
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RAD-04 · dose
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Narration of this film

A phantom, a tiny air cavity, two doses.

Requires charged-particle equilibrium across a small cavity. Spencer–Attix refines the cutoff.

Reading speed

Watch on YouTube