INGENIA

QNT-10

Particle in a 3-D box

E = (π² ħ² / 2m) (nx²/Lx² + ny²/Ly² + nz²/Lz²).

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Bound statesSchrödinger

Governing equation

E=π222m(nx2Lx2+ny2Ly2+nz2Lz2)E=\dfrac{\pi^2\hbar^2}{2m}\left(\dfrac{n_x^2}{L_x^2}+\dfrac{n_y^2}{L_y^2}+\dfrac{n_z^2}{L_z^2}\right)

where

n_x
nx ()
n_y
ny ()
n_z
nz ()
L
Cube side (nm)
E
Energy (eV)

Lecture brief

Historical brief

Planck (1900), Einstein’s photoelectric law, Bohr, de Broglie, Heisenberg and Schrödinger’s 1926 equation rebuilt matter as amplitude. These sheets are the first solvable models: wells, spin, tunneling, uncertainty. This sheet (QNT-10 — Particle in a 3-D box) is the form associated with Schrödinger. Working symbols: nxn_x, nyn_y, nzn_z, LL \rightarrow EE. Separation of variables in a rectangular well multiplies three 1-D spectra. Degeneracy appears when two sides are equal.

Purpose

Purpose: compute EE from nxn_x, nyn_y, nzn_z, LL in Quantum mechanics via E=π222m(nx2Lx2+ny2Ly2+nz2Lz2)E=\dfrac{\pi^2\hbar^2}{2m}\left(\dfrac{n_x^2}{L_x^2}+\dfrac{n_y^2}{L_y^2}+\dfrac{n_z^2}{L_z^2}\right) E = (π² ħ² / 2m) (nx²/Lx² + ny²/Ly² + nz²/Lz²). Use it when a real quantum mechanics question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given nx=1.000n_x = 1.000\,\mathrm{—}, ny=1.000n_y = 1.000\,\mathrm{—}, nz=1.000n_z = 1.000\,\mathrm{—}, L=1.000nmL = 1.000\,\mathrm{nm}, the governing relation E=π222m(nx2Lx2+ny2Ly2+nz2Lz2)E=\dfrac{\pi^2\hbar^2}{2m}\left(\dfrac{n_x^2}{L_x^2}+\dfrac{n_y^2}{L_y^2}+\dfrac{n_z^2}{L_z^2}\right) yields E=1.1281eVE = 1.1281\,\mathrm{eV}. Infinite walls, electron, lengths in nm. Move a slider: the numbers are this situation, not a canned story.

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Outputs

  • Energy E1.1281 eV
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QNT-10 · quantum
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Narration of this film

Infinite walls, electron, lengths in nm.

Separation of variables in a rectangular well multiplies three 1-D spectra. Degeneracy appears when two sides are equal.

Reading speed

Watch on YouTube