INGENIA

QNT-11

Compton wavelength shift

Δλ = λc (1 − cos θ), λc = h /(me c).

Reading speed
PhotonsCompton 1923

Governing equation

Δλ=λc(1−cos⁡θ),λc=hmec\Delta\lambda=\lambda_c(1-\cos\theta),\quad\lambda_c=\dfrac{h}{m_e c}

θ∈[0,180]\theta \in \left[0, 180\right]

where

\theta
Scatter angle (°)
\lambda
Incident wavelength (pm)
\Delta\lambda
Shift (pm)
\lambda'
Scattered wavelength (pm)

The figure, part by part

Each numbered marker wears the color of its card. Hover a card to light the marker. Tap a marker to jump to that card. The slider walks a red point along the curve; Animate drawing traces it like a pen.

QNT-11 · spectrum
00:0 / 00:08
①

Governing law — red

Δλ=λc(1−cos⁡θ),λc=hmec\Delta\lambda=\lambda_c(1-\cos\theta),\quad\lambda_c=\dfrac{h}{m_e c}

θ∈[0,180]\theta \in \left[0, 180\right]

θ=0\theta = 0Δλ=0\Delta\lambda = 0

②

Domain of the variable — blue

θmin⁡=0,θmax⁡=180\theta_{\min} = 0,\quad \theta_{\max} = 180

θ∈[0,180]\theta \in \left[0, 180\right]

θ=0\theta = 0θ=0\theta = 0

③

Response curve — green

Δλ=λc(1−cos⁡θ),λc=hmec\Delta\lambda=\lambda_c(1-\cos\theta),\quad\lambda_c=\dfrac{h}{m_e c}

θ∈[0,180]\theta \in \left[0, 180\right]

θ=0\theta = 0Δλ=0\Delta\lambda = 0

④

Rate of change — amber

dΔλdθ\frac{\mathrm{d}\Delta\lambda}{\mathrm{d}\theta}

θ∈[0,180]\theta \in \left[0, 180\right]

θ=1.132\theta = 1.132Δλ′=8.37×10−4\Delta\lambda^{\prime} = 8.37\times 10^{-4}

Lecture brief

Historical brief

Planck (1900), Einstein’s photoelectric law, Bohr, de Broglie, Heisenberg and Schrödinger’s 1926 equation rebuilt matter as amplitude. These sheets are the first solvable models: wells, spin, tunneling, uncertainty. This sheet (QNT-11 — Compton wavelength shift) is the form associated with Compton 1923. Working symbols: θ\theta, λ\lambda →\rightarrow Δλ\Delta\lambda, λ′\lambda'. Treating the photon as a particle of energy hf and momentum h/λ colliding elastically with a free electron yields Compton's shift.

Purpose

Purpose: compute Δλ\Delta\lambda, λ′\lambda' from θ\theta, λ\lambda in Quantum mechanics via Δλ=λc(1−cos⁡θ),λc=hmec\Delta\lambda=\lambda_c(1-\cos\theta),\quad\lambda_c=\dfrac{h}{m_e c} Δλ = λc (1 − cos θ), λc = h /(me c). Use it when a real quantum mechanics question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given θ=90.000 ∘\theta = 90.000\,\mathrm{^{\circ}}, λ=10.000 pm\lambda = 10.000\,\mathrm{pm}, the governing relation Δλ=λc(1−cos⁡θ),λc=hmec\Delta\lambda=\lambda_c(1-\cos\theta),\quad\lambda_c=\dfrac{h}{m_e c} yields Δλ=2.4263 pm\Delta\lambda = 2.4263\,\mathrm{pm}, λ′=12.4263 pm\lambda' = 12.4263\,\mathrm{pm}. Free electron at rest, unpolarised photon. Move a slider: the numbers are this situation, not a canned story.

Calculator

Inputs

Outputs

  • Shift \Delta\lambda2.4263 pm
  • Scattered wavelength \lambda'12.4263 pm
Reading speed

Watch on YouTube

Free library

Full library

Free PDF / open book

YouTube channels

QNT-11 · spectrum
00:0 / 00:08

Narration of this film

Free electron at rest, unpolarised photon.

Treating the photon as a particle of energy hf and momentum h/λ colliding elastically with a free electron yields Compton's shift.

Reading speed

Watch on YouTube