INGENIA

NMD-27

Bateman parent–daughter

A2 = A10 λ1/(λ2−λ1) (e^{−λ1 t} − e^{−λ2 t}). Growing-in of a daughter.

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DecayBateman

Governing equation

A2=A10λ1λ2−λ1(e−λ1t−e−λ2t)A_2=A_{10}\dfrac{\lambda_1}{\lambda_2-\lambda_1}\left(e^{-\lambda_1 t}-e^{-\lambda_2 t}\right)

t∈[0.1,200]t \in \left[0.1, 200\right]

where

A_{10}
Parent A0 (MBq)
\lambda_1
Parent λ1 (1/h)
\lambda_2
Daughter λ2 (1/h)
t
Time (h)
A_2
Daughter activity (MBq)

The figure, part by part

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NMD-27 · decay
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①

Governing law — red

A2=A10λ1λ2−λ1(e−λ1t−e−λ2t)A_2=A_{10}\dfrac{\lambda_1}{\lambda_2-\lambda_1}\left(e^{-\lambda_1 t}-e^{-\lambda_2 t}\right)

t∈[0.1,200]t \in \left[0.1, 200\right]

t=0.1t = 0.1A2=10.43A_2 = 10.43

②

Domain of the variable — blue

tmin⁡=0.1,tmax⁡=200t_{\min} = 0.1,\quad t_{\max} = 200

t∈[0.1,200]t \in \left[0.1, 200\right]

t=0.1t = 0.1t=0.1t = 0.1

③

Response curve — green

A2=A10λ1λ2−λ1(e−λ1t−e−λ2t)A_2=A_{10}\dfrac{\lambda_1}{\lambda_2-\lambda_1}\left(e^{-\lambda_1 t}-e^{-\lambda_2 t}\right)

t∈[0.1,200]t \in \left[0.1, 200\right]

t=0.1t = 0.1A2=10.43A_2 = 10.43

④

Rate of change — amber

dA2dt\frac{\mathrm{d}A_2}{\mathrm{d}t}

t∈[0.1,200]t \in \left[0.1, 200\right]

t=1.357t = 1.357A2′=88.74A_2^{\prime} = 88.74

Lecture brief

Historical brief

MIRD schema, in-vivo decay, uptake fractions and PET coincidence turned unsealed sources into organ dose. The sheets compute activity, residence and well-counter geometry. This sheet (NMD-27 — Bateman parent–daughter) is the form associated with Bateman. Working symbols: A10A_{10}, λ1\lambda_1, λ2\lambda_2, tt →\rightarrow A2A_2. The 99Mo/99mTc generator is a Bateman pair with a 66 h parent and a 6 h daughter. Transient equilibrium when λ2 > λ1.

Purpose

Purpose: compute A2A_2 from A10A_{10}, λ1\lambda_1, λ2\lambda_2, tt in Nuclear medicine via A2=A10λ1λ2−λ1(e−λ1t−e−λ2t)A_2=A_{10}\dfrac{\lambda_1}{\lambda_2-\lambda_1}\left(e^{-\lambda_1 t}-e^{-\lambda_2 t}\right) A2 = A10 λ1/(λ2−λ1) (e^{−λ1 t} − e^{−λ2 t}). Growing-in of a daughter. Use it when a real nuclear medicine question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given A10=10000.000 MBqA_{10} = 10000.000\,\mathrm{MBq}, λ1=0.011 1/h\lambda_1 = 0.011\,\mathrm{1/h}, λ2=0.116 1/h\lambda_2 = 0.116\,\mathrm{1/h}, t=24.000 ht = 24.000\,\mathrm{h}, the governing relation A2=A10λ1λ2−λ1(e−λ1t−e−λ2t)A_2=A_{10}\dfrac{\lambda_1}{\lambda_2-\lambda_1}\left(e^{-\lambda_1 t}-e^{-\lambda_2 t}\right) yields A2=714.7 MBqA_2 = 714.7\,\mathrm{MBq}. A parent decaying, a daughter rising then falling. Move a slider: the numbers are this situation, not a canned story.

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Inputs

Outputs

  • Daughter activity A_2714.7 MBq
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NMD-27 · decay
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Narration of this film

A parent decaying, a daughter rising then falling.

The 99Mo/99mTc generator is a Bateman pair with a 66 h parent and a 6 h daughter. Transient equilibrium when λ2 > λ1.

Reading speed

Watch on YouTube