INGENIA

NUC-23

Coulomb barrier

V_C = 1.44 Z₁ Z₂ / (R₁+R₂) MeV with R = 1.2 A^{1/3} fm.

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NuclearCoulomb barrier

Governing equation

VC=1.44 Z1Z2R1+R2 MeVV_C=\dfrac{1.44\,Z_1 Z_2}{R_1+R_2}\,\mathrm{MeV}

Z2∈[1,92]Z_2 \in \left[1, 92\right]

where

Z_1
Z₁ (—)
A_1
A₁ (—)
Z_2
Z₂ (—)
A_2
A₂ (—)
R_1+R_2
Contact radius (fm)
V_C
Barrier (MeV)

The figure, part by part

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NUC-23 · reactor
00:0 / 00:08
①

Governing law — red

VC=1.44 Z1Z2R1+R2 MeVV_C=\dfrac{1.44\,Z_1 Z_2}{R_1+R_2}\,\mathrm{MeV}

Z2∈[1,92]Z_2 \in \left[1, 92\right]

Z2=1Z_2 = 1R1+R2=0.338R_1+R_2 = 0.338

②

Domain of the variable — blue

Z_2_{\min} = 1,\quad Z_2_{\max} = 92

Z2∈[1,92]Z_2 \in \left[1, 92\right]

Z2=1Z_2 = 1Z2=1Z_2 = 1

③

Response curve — green

VC=1.44 Z1Z2R1+R2 MeVV_C=\dfrac{1.44\,Z_1 Z_2}{R_1+R_2}\,\mathrm{MeV}

Z2∈[1,92]Z_2 \in \left[1, 92\right]

Z2=1Z_2 = 1R1+R2=0.338R_1+R_2 = 0.338

④

Rate of change — amber

dR1+R2dZ2\frac{\mathrm{d}R_1+R_2}{\mathrm{d}Z_2}

Z2∈[1,92]Z_2 \in \left[1, 92\right]

Z2=1.572Z_2 = 1.572R1+R2′=0.338R_1+R_2^{\prime} = 0.338

Lecture brief

Historical brief

Rutherford, Chadwick, the semi-empirical mass formula, fission (Hahn–Strassmann 1938) and fusion Q-values, then Compton and Bethe–Bloch stopping, are the nuclear toolkit. Decay, binding and dose start here. This sheet (NUC-23 — Coulomb barrier) is the form associated with Coulomb barrier. Working symbols: Z1Z_1, A1A_1, Z2Z_2, A2A_2 →\rightarrow R1+R2R_1+R_2, VCV_C. The classical fusion threshold. Tunnelling and the Gamow window sit below V_C.

Purpose

Purpose: compute R1+R2R_1+R_2, VCV_C from Z1Z_1, A1A_1, Z2Z_2, A2A_2 in Nuclear physics via VC=1.44 Z1Z2R1+R2 MeVV_C=\dfrac{1.44\,Z_1 Z_2}{R_1+R_2}\,\mathrm{MeV} V_C = 1.44 Z₁ Z₂ / (R₁+R₂) MeV with R = 1.2 A^{1/3} fm. Use it when a real nuclear physics question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given Z1=1.000 —Z_1 = 1.000\,\mathrm{—}, A1=2.000 —A_1 = 2.000\,\mathrm{—}, Z2=6.000 —Z_2 = 6.000\,\mathrm{—}, A2=12.000 —A_2 = 12.000\,\mathrm{—}, the governing relation VC=1.44 Z1Z2R1+R2 MeVV_C=\dfrac{1.44\,Z_1 Z_2}{R_1+R_2}\,\mathrm{MeV} yields R1+R2=4.26 fmR_1+R_2 = 4.26\,\mathrm{fm}, VC=2.03 MeVV_C = 2.03\,\mathrm{MeV}. Two charged drops, a barrier height. Move a slider: the numbers are this situation, not a canned story.

Calculator

Inputs

Outputs

  • Contact radius R_1+R_24.26 fm
  • Barrier V_C2.03 MeV
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NUC-23 · reactor
00:0 / 00:08

Narration of this film

Two charged drops, a barrier height.

The classical fusion threshold. Tunnelling and the Gamow window sit below V_C.

Reading speed

Watch on YouTube