INGENIA

FLD-05

Poiseuille discharge

Q = π r⁴ Δp / (8 μ L). Laminar flow in a circular tube.

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FluidsPoiseuille

Governing equation

Q=πr4Δp8μLQ=\dfrac{\pi r^4\Delta p}{8\mu L}

r∈[0.05,20]r \in \left[0.05, 20\right]

where

r
Radius (mm)
\Delta p
Pressure drop (kPa)
\mu
Viscosity (Pa·s)
L
Length (m)
Q
Discharge (mL/s)

The figure, part by part

Each numbered marker wears the color of its card. Hover a card to light the marker. Tap a marker to jump to that card. The slider walks a red point along the curve; Animate drawing traces it like a pen.

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①

Governing law — red

Q=πr4Δp8μLQ=\dfrac{\pi r^4\Delta p}{8\mu L}

r∈[0.05,20]r \in \left[0.05, 20\right]

r=0.05r = 0.05Q=4.91×10−6Q = 4.91\times 10^{-6}

②

Domain of the variable — blue

rmin⁡=0.05,rmax⁡=20r_{\min} = 0.05,\quad r_{\max} = 20

r∈[0.05,20]r \in \left[0.05, 20\right]

r=0.05r = 0.05r=0.05r = 0.05

③

Response curve — green

Q=πr4Δp8μLQ=\dfrac{\pi r^4\Delta p}{8\mu L}

r∈[0.05,20]r \in \left[0.05, 20\right]

r=0.05r = 0.05Q=4.91×10−6Q = 4.91\times 10^{-6}

④

Rate of change — amber

dQdr\frac{\mathrm{d}Q}{\mathrm{d}r}

r∈[0.05,20]r \in \left[0.05, 20\right]

r=0.175r = 0.175Q′=0.026Q^{\prime} = 0.026

Lecture brief

Historical brief

Bernoulli, Navier–Stokes, Reynolds (1883) and Stokes drag made continuum flow a dimensionless craft. The sheets compute head, drag, Re and a pedagogical NS snapshot. This sheet (FLD-05 — Poiseuille discharge) is the form associated with Poiseuille. Working symbols: rr, Δp\Delta p, μ\mu, LL →\rightarrow QQ. The r⁴ law: halving the radius cuts the flow sixteenfold. Blood vessels live here.

Purpose

Purpose: compute QQ from rr, Δp\Delta p, μ\mu, LL in Fluid physics via Q=πr4Δp8μLQ=\dfrac{\pi r^4\Delta p}{8\mu L} Q = π r⁴ Δp / (8 μ L). Laminar flow in a circular tube. Use it when a real fluid physics question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given r=1.000 mmr = 1.000\,\mathrm{mm}, Δp=2.000 kPa\Delta p = 2.000\,\mathrm{kPa}, μ=0.001 Pa⋅s\mu = 0.001\,\mathrm{Pa·s}, L=1.000 mL = 1.000\,\mathrm{m}, the governing relation Q=πr4Δp8μLQ=\dfrac{\pi r^4\Delta p}{8\mu L} yields Q=0.7854 mL/sQ = 0.7854\,\mathrm{mL/s}. A capillary, a parabolic profile, a volume flux. Move a slider: the numbers are this situation, not a canned story.

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Inputs

Outputs

  • Discharge Q0.7854 mL/s
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Narration of this film

A capillary, a parabolic profile, a volume flux.

The r⁴ law: halving the radius cuts the flow sixteenfold. Blood vessels live here.

Reading speed

Watch on YouTube