INGENIA

EMG-06

Series RLC impedance

Z = √(R² + (ωL − 1/(ωC))²).

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AC circuitsSteinmetz

Governing equation

Z=R2+(ωL1ωC)2Z=\sqrt{R^2+\left(\omega L-\dfrac{1}{\omega C}\right)^2}

where

R
Resistance (Ω)
L
Inductance (mH)
C
Capacitance (µF)
f
Frequency (Hz)
Z
Impedance (Ω)
\varphi
Phase (°)

Lecture brief

Historical brief

Coulomb, Gauss, Ampère, Faraday and Maxwell (1861–65) unified charge, current and light. The lab computes fields, induction, Poynting flux and the electromagnetic wave in SI. This sheet (EMG-06 — Series RLC impedance) is the form associated with Steinmetz. Working symbols: RR, LL, CC, ff \rightarrow ZZ, φ\varphi. Phasor addition of resistance and the two reactances yields the magnitude of series impedance, minimum at resonance.

Purpose

Purpose: compute ZZ, φ\varphi from RR, LL, CC, ff in Electromagnetism via Z=R2+(ωL1ωC)2Z=\sqrt{R^2+\left(\omega L-\dfrac{1}{\omega C}\right)^2} Z = √(R² + (ωL − 1/(ωC))²). Use it when a real electromagnetism question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given R=10.000ΩR = 10.000\,\mathrm{Ω}, L=25.000mHL = 25.000\,\mathrm{mH}, C=40.000μFC = 40.000\,\mathrm{\mu F}, f=50.000Hzf = 50.000\,\mathrm{Hz}, the governing relation Z=R2+(ωL1ωC)2Z=\sqrt{R^2+\left(\omega L-\dfrac{1}{\omega C}\right)^2} yields Z=72.417ΩZ = 72.417\,\mathrm{Ω}, φ=82.063\varphi = -82.063\,\mathrm{^{\circ}}. Linear lumped R, L, C driven by a sinusoid. Move a slider: the numbers are this situation, not a canned story.

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Inputs

Outputs

  • Impedance Z72.417 Ω
  • Phase \varphi-82.063 °
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EMG-06 · circuit
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Narration of this film

Linear lumped R, L, C driven by a sinusoid.

Phasor addition of resistance and the two reactances yields the magnitude of series impedance, minimum at resonance.

Reading speed

Watch on YouTube