INGENIA

EMG-05

Poynting vector of a plane wave

S = E B / μ0 = E² / Z0 for a vacuum plane wave.

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Electromagnetic wavesPoynting 1884

Governing equation

S=EBμ0=E2Z0,Z0=μ0/ε0S=\dfrac{E B}{\mu_0}=\dfrac{E^2}{Z_0},\quad Z_0=\sqrt{\mu_0/\varepsilon_0}

where

E
Electric field (peak) (V/m)
S
Peak Poynting (W/m²)
B
Peak B (µT)

Lecture brief

Historical brief

Coulomb, Gauss, Ampère, Faraday and Maxwell (1861–65) unified charge, current and light. The lab computes fields, induction, Poynting flux and the electromagnetic wave in SI. This sheet (EMG-05 — Poynting vector of a plane wave) is the form associated with Poynting 1884. Working symbols: EE \rightarrow SS, BB. Poynting identified S = E×H as the energy-flux density. In a TEM plane wave |H| = |E|/Z0 so |S| = E²/Z0.

Purpose

Purpose: compute SS, BB from EE in Electromagnetism via S=EBμ0=E2Z0,Z0=μ0/ε0S=\dfrac{E B}{\mu_0}=\dfrac{E^2}{Z_0},\quad Z_0=\sqrt{\mu_0/\varepsilon_0} S = E B / μ0 = E² / Z0 for a vacuum plane wave. Use it when a real electromagnetism question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given E=100.000V/mE = 100.000\,\mathrm{V/m}, the governing relation S=EBμ0=E2Z0,Z0=μ0/ε0S=\dfrac{E B}{\mu_0}=\dfrac{E^2}{Z_0},\quad Z_0=\sqrt{\mu_0/\varepsilon_0} yields S=26.544W/m2S = 26.544\,\mathrm{W/m^{2}}, B=0.333564μTB = 0.333564\,\mathrm{\mu T}. RMS or peak consistently: here E is peak, S is instantaneous peak. Move a slider: the numbers are this situation, not a canned story.

Calculator

Inputs

Outputs

  • Peak Poynting S26.544 W/m²
  • Peak B B0.333564 µT
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EMG-05 · wave
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Narration of this film

RMS or peak consistently: here E is peak, S is instantaneous peak.

Poynting identified S = E×H as the energy-flux density. In a TEM plane wave |H| = |E|/Z0 so |S| = E²/Z0.

Reading speed

Watch on YouTube