INGENIA

EMG-10

Parallel-plate capacitor

C = ε0 εr A / d, E = V/d.

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CapacitanceCavendish / Maxwell

Governing equation

C=ε0εrAd,E=VdC=\varepsilon_0\varepsilon_r\dfrac{A}{d},\quad E=\dfrac{V}{d}

d∈[0.1,20]d \in \left[0.1, 20\right]

where

A
Area (cm²)
d
Gap (mm)
\varepsilon_r
Relative permittivity (—)
V
Voltage (V)
C
Capacitance (pF)
E
Field (kV/m)

The figure, part by part

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EMG-10 · circuit
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①

Governing law — red

C=ε0εrAd,E=VdC=\varepsilon_0\varepsilon_r\dfrac{A}{d},\quad E=\dfrac{V}{d}

d∈[0.1,20]d \in \left[0.1, 20\right]

d=0.1d = 0.1C=885.4C = 885.4

②

Domain of the variable — blue

dmin⁡=0.1,dmax⁡=20d_{\min} = 0.1,\quad d_{\max} = 20

d∈[0.1,20]d \in \left[0.1, 20\right]

d=0.1d = 0.1d=0.1d = 0.1

③

Response curve — green

C=ε0εrAd,E=VdC=\varepsilon_0\varepsilon_r\dfrac{A}{d},\quad E=\dfrac{V}{d}

d∈[0.1,20]d \in \left[0.1, 20\right]

d=0.1d = 0.1C=885.4C = 885.4

④

Rate of change — amber

dCdd\frac{\mathrm{d}C}{\mathrm{d}d}

d∈[0.1,20]d \in \left[0.1, 20\right]

d=0.225d = 0.225C′=−2527.5C^{\prime} = -2527.5

Lecture brief

Historical brief

Coulomb, Gauss, Ampère, Faraday and Maxwell (1861–65) unified charge, current and light. The lab computes fields, induction, Poynting flux and the electromagnetic wave in SI. This sheet (EMG-10 — Parallel-plate capacitor) is the form associated with Cavendish / Maxwell. Working symbols: AA, dd, εr\varepsilon_r, VV →\rightarrow CC, EE. Gauss's law between infinite plates gives σ/ε, so C = Q/V = ε A/d. A dielectric multiplies ε0 by εr.

Purpose

Purpose: compute CC, EE from AA, dd, εr\varepsilon_r, VV in Electromagnetism via C=ε0εrAd,E=VdC=\varepsilon_0\varepsilon_r\dfrac{A}{d},\quad E=\dfrac{V}{d} C = ε0 εr A / d, E = V/d. Use it when a real electromagnetism question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given A=100.000 cm2A = 100.000\,\mathrm{cm^{2}}, d=1.000 mmd = 1.000\,\mathrm{mm}, εr=1.000 —\varepsilon_r = 1.000\,\mathrm{—}, V=12.000 VV = 12.000\,\mathrm{V}, the governing relation C=ε0εrAd,E=VdC=\varepsilon_0\varepsilon_r\dfrac{A}{d},\quad E=\dfrac{V}{d} yields C=88.542 pFC = 88.542\,\mathrm{pF}, E=12.000 kV/mE = 12.000\,\mathrm{kV/m}. Fringing neglected, linear dielectric. Move a slider: the numbers are this situation, not a canned story.

Calculator

Inputs

Outputs

  • Capacitance C88.542 pF
  • Field E12.000 kV/m
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EMG-10 · circuit
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Narration of this film

Fringing neglected, linear dielectric.

Gauss's law between infinite plates gives σ/ε, so C = Q/V = ε A/d. A dielectric multiplies ε0 by εr.

Reading speed

Watch on YouTube