INGENIA

EMG-02

Gauss field of a point charge

E = Q /(4π ε0 r²) from Gauss's law.

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ElectrostaticsGauss 1835 / Maxwell

Governing equation

E=Q4πε0r2,EdA=Qε0E=\dfrac{Q}{4\pi\varepsilon_0 r^2},\quad \oint\mathbf{E}\cdot d\mathbf{A}=\dfrac{Q}{\varepsilon_0}

where

Q
Charge (nC)
r
Radius (m)
E
Electric field (N/C)

Lecture brief

Historical brief

Coulomb, Gauss, Ampère, Faraday and Maxwell (1861–65) unified charge, current and light. The lab computes fields, induction, Poynting flux and the electromagnetic wave in SI. This sheet (EMG-02 — Gauss field of a point charge) is the form associated with Gauss 1835 / Maxwell. Working symbols: QQ, rr \rightarrow EE. ∮ E·dA = Qenc/ε0 plus spherical symmetry forces E radial and constant on a Gaussian sphere, recovering Coulomb's field.

Purpose

Purpose: compute EE from QQ, rr in Electromagnetism via E=Q4πε0r2,EdA=Qε0E=\dfrac{Q}{4\pi\varepsilon_0 r^2},\quad \oint\mathbf{E}\cdot d\mathbf{A}=\dfrac{Q}{\varepsilon_0} E = Q /(4π ε0 r²) from Gauss's law. Use it when a real electromagnetism question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given Q=5.000nCQ = 5.000\,\mathrm{nC}, r=0.200mr = 0.200\,\mathrm{m}, the governing relation E=Q4πε0r2,EdA=Qε0E=\dfrac{Q}{4\pi\varepsilon_0 r^2},\quad \oint\mathbf{E}\cdot d\mathbf{A}=\dfrac{Q}{\varepsilon_0} yields E=1123.444N/CE = 1123.444\,\mathrm{N/C}. Vacuum, point charge, r > 0. Move a slider: the numbers are this situation, not a canned story.

Calculator

Inputs

Outputs

  • Electric field E1123.444 N/C
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EMG-02 · gauge
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Narration of this film

Vacuum, point charge, r > 0.

∮ E·dA = Qenc/ε0 plus spherical symmetry forces E radial and constant on a Gaussian sphere, recovering Coulomb's field.

Reading speed

Watch on YouTube