INGENIA

CLS-03

Linear momentum

p = m v, and F = dp/dt.

Reading speed
MomentumNewton 1687

Governing equation

p=mv,F=dpdtp=mv,\quad F=\dfrac{\mathrm{d}p}{\mathrm{d}t}

v∈[−100,100]v \in \left[-100, 100\right]

where

m
Mass (kg)
v
Velocity (m/s)
p
Momentum (kg·m/s)

The figure, part by part

Each numbered marker wears the color of its card. Hover a card to light the marker. Tap a marker to jump to that card. The slider walks a red point along the curve; Animate drawing traces it like a pen.

CLS-03 · projectile
00:0 / 00:08
①

Governing law — red

p=mv,F=dpdtp=mv,\quad F=\dfrac{\mathrm{d}p}{\mathrm{d}t}

v∈[−100,100]v \in \left[-100, 100\right]

v=−100v = -100p=−300p = -300

②

Domain of the variable — blue

vmin⁡=−100,vmax⁡=100v_{\min} = -100,\quad v_{\max} = 100

v∈[−100,100]v \in \left[-100, 100\right]

v=−100v = -100v=−100v = -100

③

Response curve — green

p=mv,F=dpdtp=mv,\quad F=\dfrac{\mathrm{d}p}{\mathrm{d}t}

v∈[−100,100]v \in \left[-100, 100\right]

v=−100v = -100p=−300p = -300

④

Rate of change — amber

dpdv\frac{\mathrm{d}p}{\mathrm{d}v}

v∈[−100,100]v \in \left[-100, 100\right]

v=−98.74v = -98.74p′=3p^{\prime} = 3

Lecture brief

Historical brief

Newtonian mechanics (1687) plus energy, angular momentum, Kepler and the ballistic parabola remain the first language of motion. Every sheet here is a closed-form orbit, throw, spin or oscillator. This sheet (CLS-03 — Linear momentum) is the form associated with Newton 1687. Working symbols: mm, vv →\rightarrow pp. Newton's 'quantity of motion' is mass times velocity. Its time derivative is the net force, so p is conserved when F = 0.

Purpose

Purpose: compute pp from mm, vv in Classical mechanics via p=mv,F=dpdtp=mv,\quad F=\dfrac{\mathrm{d}p}{\mathrm{d}t} p = m v, and F = dp/dt. Use it when a real classical mechanics question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given m=3.000 kgm = 3.000\,\mathrm{kg}, v=8.000 m/sv = 8.000\,\mathrm{m/s}, the governing relation p=mv,F=dpdtp=mv,\quad F=\dfrac{\mathrm{d}p}{\mathrm{d}t} yields p=24.000 kg⋅m/sp = 24.000\,\mathrm{kg·m/s}. Particle of constant mass. Move a slider: the numbers are this situation, not a canned story.

Calculator

Inputs

Outputs

  • Momentum p24.000 kg·m/s
Reading speed

Watch on YouTube

Free library

Full library

Free PDF / open book

YouTube channels

CLS-03 · projectile
00:0 / 00:08

Narration of this film

Particle of constant mass.

Newton's 'quantity of motion' is mass times velocity. Its time derivative is the net force, so p is conserved when F = 0.

Reading speed

Watch on YouTube