INGENIA

CLS-12

Escape velocity

v_esc = √(2 G M / R) from a spherical mass.

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GravityNewton

Governing equation

vesc=2GMRv_{\mathrm{esc}}=\sqrt{\dfrac{2GM}{R}}

R∈[10,1×106]R \in \left[10, 1\times 10^{6}\right]

where

M
Mass (kg)
R
Radius (km)
v_{\mathrm{esc}}
Escape speed (km/s)

The figure, part by part

Each numbered marker wears the color of its card. Hover a card to light the marker. Tap a marker to jump to that card. The slider walks a red point along the curve; Animate drawing traces it like a pen.

CLS-12 · orbit
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①

Governing law — red

vesc=2GMRv_{\mathrm{esc}}=\sqrt{\dfrac{2GM}{R}}

R∈[10,1×106]R \in \left[10, 1\times 10^{6}\right]

R=10R = 10vesc=282.3v_{\mathrm{esc}} = 282.3

②

Domain of the variable — blue

Rmin⁡=10,Rmax⁡=1×106R_{\min} = 10,\quad R_{\max} = 1\times 10^{6}

R∈[10,1×106]R \in \left[10, 1\times 10^{6}\right]

R=10R = 10R=10R = 10

③

Response curve — green

vesc=2GMRv_{\mathrm{esc}}=\sqrt{\dfrac{2GM}{R}}

R∈[10,1×106]R \in \left[10, 1\times 10^{6}\right]

R=10R = 10vesc=282.3v_{\mathrm{esc}} = 282.3

④

Rate of change — amber

dvescdR\frac{\mathrm{d}v_{\mathrm{esc}}}{\mathrm{d}R}

R∈[10,1×106]R \in \left[10, 1\times 10^{6}\right]

R=6299.2R = 6299.2vesc′=−0.022v_{\mathrm{esc}}^{\prime} = -0.022

Lecture brief

Historical brief

Newtonian mechanics (1687) plus energy, angular momentum, Kepler and the ballistic parabola remain the first language of motion. Every sheet here is a closed-form orbit, throw, spin or oscillator. This sheet (CLS-12 — Escape velocity) is the form associated with Newton. Working symbols: MM, RR →\rightarrow vescv_{\mathrm{esc}}. Setting total mechanical energy to zero on a 1/r potential gives the speed that just reaches infinity, √(2GM/R).

Purpose

Purpose: compute vescv_{\mathrm{esc}} from MM, RR in Classical mechanics via vesc=2GMRv_{\mathrm{esc}}=\sqrt{\dfrac{2GM}{R}} v_esc = √(2 G M / R) from a spherical mass. Use it when a real classical mechanics question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given M=5.972e+24 kgM = 5.972e+24\,\mathrm{kg}, R=6371.000 kmR = 6371.000\,\mathrm{km}, the governing relation vesc=2GMRv_{\mathrm{esc}}=\sqrt{\dfrac{2GM}{R}} yields vesc=11.186 km/sv_{\mathrm{esc}} = 11.186\,\mathrm{km/s}. Non-rotating sphere, no atmosphere, Newtonian. Move a slider: the numbers are this situation, not a canned story.

Calculator

Inputs

Outputs

  • Escape speed v_{\mathrm{esc}}11.186 km/s
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CLS-12 · orbit
00:0 / 00:08

Narration of this film

Non-rotating sphere, no atmosphere, Newtonian.

Setting total mechanical energy to zero on a 1/r potential gives the speed that just reaches infinity, √(2GM/R).

Reading speed

Watch on YouTube