INGENIA

CLS-15

Simple harmonic period

T = 2π √(m/k) for a mass on a Hookean spring.

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NewtonianSHM

Governing equation

T=2πm/kT=2\pi\sqrt{m/k}

where

m
Mass (kg)
k
Stiffness (N/m)
T
Period (s)

Lecture brief

Historical brief

Newtonian mechanics (1687) plus energy, angular momentum, Kepler and the ballistic parabola remain the first language of motion. Every sheet here is a closed-form orbit, throw, spin or oscillator. This sheet (CLS-15 — Simple harmonic period) is the form associated with SHM. Working symbols: mm, kk \rightarrow TT. The ODE is ẍ + (k/m) x = 0. ω = √(k/m) is independent of amplitude.

Purpose

Purpose: compute TT from mm, kk in Classical mechanics via T=2πm/kT=2\pi\sqrt{m/k} T = 2π √(m/k) for a mass on a Hookean spring. Use it when a real classical mechanics question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given m=0.400kgm = 0.400\,\mathrm{kg}, k=40.000N/mk = 40.000\,\mathrm{N/m}, the governing relation T=2πm/kT=2\pi\sqrt{m/k} yields T=0.628sT = 0.628\,\mathrm{s}. A spring, a mass, a ticking period. Move a slider: the numbers are this situation, not a canned story.

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Inputs

Outputs

  • Period T0.628 s
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CLS-15 · pendulum
00:0 / 00:08

Narration of this film

A spring, a mass, a ticking period.

The ODE is ẍ + (k/m) x = 0. ω = √(k/m) is independent of amplitude.

Reading speed

Watch on YouTube