INGENIA

CLS-10

Angular momentum of a rigid rotor

L = I ω, and τ = dL/dt.

Reading speed
RotationKepler / Newton

Governing equation

L=Iω,τ=dLdtL=I\omega,\quad \tau=\dfrac{\mathrm{d}L}{\mathrm{d}t}

ω∈[−100,100]\omega \in \left[-100, 100\right]

where

I
Inertia (kg·m²)
\omega
Angular speed (rad/s)
L
Angular momentum (kg·m²/s)

The figure, part by part

Each numbered marker wears the color of its card. Hover a card to light the marker. Tap a marker to jump to that card. The slider walks a red point along the curve; Animate drawing traces it like a pen.

CLS-10 · pendulum
00:0 / 00:08
①

Governing law — red

L=Iω,τ=dLdtL=I\omega,\quad \tau=\dfrac{\mathrm{d}L}{\mathrm{d}t}

ω∈[−100,100]\omega \in \left[-100, 100\right]

ω=−100\omega = -100L=−300L = -300

②

Domain of the variable — blue

ωmin⁡=−100,ωmax⁡=100\omega_{\min} = -100,\quad \omega_{\max} = 100

ω∈[−100,100]\omega \in \left[-100, 100\right]

ω=−100\omega = -100ω=−100\omega = -100

③

Response curve — green

L=Iω,τ=dLdtL=I\omega,\quad \tau=\dfrac{\mathrm{d}L}{\mathrm{d}t}

ω∈[−100,100]\omega \in \left[-100, 100\right]

ω=−100\omega = -100L=−300L = -300

④

Rate of change — amber

dLdω\frac{\mathrm{d}L}{\mathrm{d}\omega}

ω∈[−100,100]\omega \in \left[-100, 100\right]

ω=−98.74\omega = -98.74L′=3L^{\prime} = 3

Lecture brief

Historical brief

Newtonian mechanics (1687) plus energy, angular momentum, Kepler and the ballistic parabola remain the first language of motion. Every sheet here is a closed-form orbit, throw, spin or oscillator. This sheet (CLS-10 — Angular momentum of a rigid rotor) is the form associated with Kepler / Newton. Working symbols: II, ω\omega →\rightarrow LL. For a rigid body about a principal axis, L = I ω. Vanishing torque conserves L, Kepler's areal law in disguise.

Purpose

Purpose: compute LL from II, ω\omega in Classical mechanics via L=Iω,τ=dLdtL=I\omega,\quad \tau=\dfrac{\mathrm{d}L}{\mathrm{d}t} L = I ω, and τ = dL/dt. Use it when a real classical mechanics question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given I=3.000 kg⋅m2I = 3.000\,\mathrm{kg·m^{2}}, ω=15.000 rad/s\omega = 15.000\,\mathrm{rad/s}, the governing relation L=Iω,τ=dLdtL=I\omega,\quad \tau=\dfrac{\mathrm{d}L}{\mathrm{d}t} yields L=45.000 kg⋅m2/sL = 45.000\,\mathrm{kg·m^{2}/s}. Fixed principal axis, rigid. Move a slider: the numbers are this situation, not a canned story.

Calculator

Inputs

Outputs

  • Angular momentum L45.000 kg·m²/s
Reading speed

Watch on YouTube

Free library

Full library

Free PDF / open book

YouTube channels

CLS-10 · pendulum
00:0 / 00:08

Narration of this film

Fixed principal axis, rigid.

For a rigid body about a principal axis, L = I ω. Vanishing torque conserves L, Kepler's areal law in disguise.

Reading speed

Watch on YouTube