INGENIA

CLS-10

Angular momentum of a rigid rotor

L = I ω, and τ = dL/dt.

Reading speed
RotationKepler / Newton

Governing equation

L=Iω,τ=dLdtL=I\omega,\quad \tau=\dfrac{\mathrm{d}L}{\mathrm{d}t}

where

I
Inertia (kg·m²)
\omega
Angular speed (rad/s)
L
Angular momentum (kg·m²/s)

Lecture brief

Historical brief

Newtonian mechanics (1687) plus energy, angular momentum, Kepler and the ballistic parabola remain the first language of motion. Every sheet here is a closed-form orbit, throw, spin or oscillator. This sheet (CLS-10 — Angular momentum of a rigid rotor) is the form associated with Kepler / Newton. Working symbols: II, ω\omega \rightarrow LL. For a rigid body about a principal axis, L = I ω. Vanishing torque conserves L, Kepler's areal law in disguise.

Purpose

Purpose: compute LL from II, ω\omega in Classical mechanics via L=Iω,τ=dLdtL=I\omega,\quad \tau=\dfrac{\mathrm{d}L}{\mathrm{d}t} L = I ω, and τ = dL/dt. Use it when a real classical mechanics question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given I=3.000kgm2I = 3.000\,\mathrm{kg·m^{2}}, ω=15.000rad/s\omega = 15.000\,\mathrm{rad/s}, the governing relation L=Iω,τ=dLdtL=I\omega,\quad \tau=\dfrac{\mathrm{d}L}{\mathrm{d}t} yields L=45.000kgm2/sL = 45.000\,\mathrm{kg·m^{2}/s}. Fixed principal axis, rigid. Move a slider: the numbers are this situation, not a canned story.

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Inputs

Outputs

  • Angular momentum L45.000 kg·m²/s
Reading speed

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CLS-10 · pendulum
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Narration of this film

Fixed principal axis, rigid.

For a rigid body about a principal axis, L = I ω. Vanishing torque conserves L, Kepler's areal law in disguise.

Reading speed

Watch on YouTube