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CAL-04

Taylor polynomial of degree 2

T2(x) = f + f' h + ½ f'' h², h = x − a.

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SeriesTaylor

Governing equation

T2(a+h)=f+fh+12fh2T_2(a+h)=f+f'h+\tfrac12 f'' h^2

where

f
f(a) ()
f'
f'(a) ()
f''
f''(a) ()
h
Step h ()
T_2
Taylor value ()

Lecture brief

Historical brief

Newton and Leibniz (1670s), Taylor, the fundamental theorem and the trapezoid rule are how change became a number. The lab differentiates, integrates and linearises in one variable. This sheet (CAL-04 — Taylor polynomial of degree 2) is the form associated with Taylor. Working symbols: ff, ff', ff'', hh \rightarrow T2T_2. The unique quadratic that matches f, f', f'' at a. Remainder ~ h³ f'''(ξ)/6.

Purpose

Purpose: compute T2T_2 from ff, ff', ff'', hh in Calculus via T2(a+h)=f+fh+12fh2T_2(a+h)=f+f'h+\tfrac12 f'' h^2 T2(x) = f + f' h + ½ f'' h², h = x − a. Use it when a real calculus question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given f=1.000f = 1.000\,\mathrm{—}, f=0.500f' = 0.500\,\mathrm{—}, f=2.000f'' = -2.000\,\mathrm{—}, h=0.200h = 0.200\,\mathrm{—}, the governing relation T2(a+h)=f+fh+12fh2T_2(a+h)=f+f'h+\tfrac12 f'' h^2 yields T2=1.0600T_2 = 1.0600\,\mathrm{—}. Enter jets at a and a step h. Move a slider: the numbers are this situation, not a canned story.

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Inputs

Outputs

  • Taylor value T_21.0600
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Narration of this film

Enter jets at a and a step h.

The unique quadratic that matches f, f', f'' at a. Remainder ~ h³ f'''(ξ)/6.

Reading speed

Watch on YouTube