INGENIA

CAL-17

Power integral

∫ x^n dx = x^{n+1}/(n+1) + C, n ≠ −1.

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IntegralsPower integral

Governing equation

0xtndt=xn+1n+1\int_0^x t^n\,dt=\dfrac{x^{n+1}}{n+1}

where

n
Exponent ()
x
Upper limit ()
I
Integral ()

Lecture brief

Historical brief

Newton and Leibniz (1670s), Taylor, the fundamental theorem and the trapezoid rule are how change became a number. The lab differentiates, integrates and linearises in one variable. This sheet (CAL-17 — Power integral) is the form associated with Power integral. Working symbols: nn, xx \rightarrow II. The inverse of the power rule. n = −1 is ln|x|.

Purpose

Purpose: compute II from nn, xx in Calculus via 0xtndt=xn+1n+1\int_0^x t^n\,dt=\dfrac{x^{n+1}}{n+1} ∫ x^n dx = x^{n+1}/(n+1) + C, n ≠ −1. Use it when a real calculus question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given n=2.000n = 2.000\,\mathrm{—}, x=3.000x = 3.000\,\mathrm{—}, the governing relation 0xtndt=xn+1n+1\int_0^x t^n\,dt=\dfrac{x^{n+1}}{n+1} yields I=9.0000I = 9.0000\,\mathrm{—}. Evaluate the definite integral from 0 to x (n > −1). Move a slider: the numbers are this situation, not a canned story.

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Inputs

Outputs

  • Integral I9.0000
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Narration of this film

Evaluate the definite integral from 0 to x (n > −1).

The inverse of the power rule. n = −1 is ln|x|.

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Watch on YouTube