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CAL-10

Implicit derivative snapshot

F(x,y) = c ⇒ dy/dx = −Fx / Fy. Slope of a level curve.

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DerivativesImplicit differentiation

Governing equation

dydx=−FxFy\dfrac{dy}{dx}=-\dfrac{F_x}{F_y}

Fx∈[−20,20]F_x \in \left[-20, 20\right]

where

F_x
∂F/∂x (—)
F_y
∂F/∂y (—)
y'
Implicit slope (—)

The figure, part by part

Each numbered marker wears the color of its card. Hover a card to light the marker. Tap a marker to jump to that card. The slider walks a red point along the curve; Animate drawing traces it like a pen.

CAL-10 · curve
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①

Governing law — red

dydx=−FxFy\dfrac{dy}{dx}=-\dfrac{F_x}{F_y}

Fx∈[−20,20]F_x \in \left[-20, 20\right]

Fx=−20F_x = -20y′=5y' = 5

②

Domain of the variable — blue

F_x_{\min} = -20,\quad F_x_{\max} = 20

Fx∈[−20,20]F_x \in \left[-20, 20\right]

Fx=−20F_x = -20Fx=−20F_x = -20

③

Response curve — green

dydx=−FxFy\dfrac{dy}{dx}=-\dfrac{F_x}{F_y}

Fx∈[−20,20]F_x \in \left[-20, 20\right]

Fx=−20F_x = -20y′=5y' = 5

④

Rate of change — amber

dy′dFx\frac{\mathrm{d}y'}{\mathrm{d}F_x}

Fx∈[−20,20]F_x \in \left[-20, 20\right]

Fx=−19.75F_x = -19.75y′′=−0.25y'^{\prime} = -0.25

Lecture brief

Historical brief

Newton and Leibniz (1670s), Taylor, the fundamental theorem and the trapezoid rule are how change became a number. The lab differentiates, integrates and linearises in one variable. This sheet (CAL-10 — Implicit derivative snapshot) is the form associated with Implicit differentiation. Working symbols: FxF_x, FyF_y →\rightarrow y′y'. Chain rule on F(x, y(x)) = c. The gradient is orthogonal to the level set.

Purpose

Purpose: compute y′y' from FxF_x, FyF_y in Calculus via dydx=−FxFy\dfrac{dy}{dx}=-\dfrac{F_x}{F_y} F(x,y) = c ⇒ dy/dx = −Fx / Fy. Slope of a level curve. Use it when a real calculus question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given Fx=2.000 —F_x = 2.000\,\mathrm{—}, Fy=4.000 —F_y = 4.000\,\mathrm{—}, the governing relation dydx=−FxFy\dfrac{dy}{dx}=-\dfrac{F_x}{F_y} yields y′=−0.5000 —y' = -0.5000\,\mathrm{—}. Enter partials Fx, Fy at a point on the curve. Move a slider: the numbers are this situation, not a canned story.

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Inputs

Outputs

  • Implicit slope y'-0.5000 —
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CAL-10 · curve
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Narration of this film

Enter partials Fx, Fy at a point on the curve.

Chain rule on F(x, y(x)) = c. The gradient is orthogonal to the level set.

Reading speed

Watch on YouTube