INGENIA

CAL-03

Chain rule

(f∘g)' = f'(g) g'. Composition of rates.

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DerivativesChain rule

Governing equation

(f∘g)′=f′(g) g′(f\circ g)'=f'(g)\,g'

f′(g)∈[−30,30]f'(g) \in \left[-30, 30\right]

where

f'(g)
Outer derivative (—)
g'
Inner derivative (—)
(f\circ g)'
Chain derivative (—)

The figure, part by part

Each numbered marker wears the color of its card. Hover a card to light the marker. Tap a marker to jump to that card. The slider walks a red point along the curve; Animate drawing traces it like a pen.

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①

Governing law — red

(f∘g)′=f′(g) g′(f\circ g)'=f'(g)\,g'

f′(g)∈[−30,30]f'(g) \in \left[-30, 30\right]

f′(g)=−30f'(g) = -30(f∘g)′=−15(f\circ g)' = -15

②

Domain of the variable — blue

f′(g)min⁡=−30,f′(g)max⁡=30f'(g)_{\min} = -30,\quad f'(g)_{\max} = 30

f′(g)∈[−30,30]f'(g) \in \left[-30, 30\right]

f′(g)=−30f'(g) = -30f′(g)=−30f'(g) = -30

③

Response curve — green

(f∘g)′=f′(g) g′(f\circ g)'=f'(g)\,g'

f′(g)∈[−30,30]f'(g) \in \left[-30, 30\right]

f′(g)=−30f'(g) = -30(f∘g)′=−15(f\circ g)' = -15

④

Rate of change — amber

d(f∘g)′df′(g)\frac{\mathrm{d}(f\circ g)'}{\mathrm{d}f'(g)}

f′(g)∈[−30,30]f'(g) \in \left[-30, 30\right]

f′(g)=−29.62f'(g) = -29.62(f∘g)′′=0.5(f\circ g)'^{\prime} = 0.5

Lecture brief

Historical brief

Newton and Leibniz (1670s), Taylor, the fundamental theorem and the trapezoid rule are how change became a number. The lab differentiates, integrates and linearises in one variable. This sheet (CAL-03 — Chain rule) is the form associated with Chain rule. Working symbols: f′(g)f'(g), g′g' →\rightarrow (f∘g)′(f\circ g)'. Leibniz: dy/dx = (dy/du)(du/dx). The Jacobian of a composition is a product of Jacobians.

Purpose

Purpose: compute (f∘g)′(f\circ g)' from f′(g)f'(g), g′g' in Calculus via (f∘g)′=f′(g) g′(f\circ g)'=f'(g)\,g' (f∘g)' = f'(g) g'. Composition of rates. Use it when a real calculus question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given f′(g)=4.000 —f'(g) = 4.000\,\mathrm{—}, g′=0.500 —g' = 0.500\,\mathrm{—}, the governing relation (f∘g)′=f′(g) g′(f\circ g)'=f'(g)\,g' yields (f∘g)′=2.0000 —(f\circ g)' = 2.0000\,\mathrm{—}. Enter f'(g) and g' at the evaluation point. Move a slider: the numbers are this situation, not a canned story.

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Outputs

  • Chain derivative (f\circ g)'2.0000 —
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Narration of this film

Enter f'(g) and g' at the evaluation point.

Leibniz: dy/dx = (dy/du)(du/dx). The Jacobian of a composition is a product of Jacobians.

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