INGENIA

ATM-03

Bohr radius

a₀ = 4π ε₀ ħ² / (m e²) ≈ 0.529 Å, r_n = n² a₀ / Z.

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StructureBohr radius

Governing equation

rn=n2a0/Z,a0=4πε02/me2r_n=n^2 a_0/Z,\quad a_0=4\pi\varepsilon_0\hbar^2/me^2

where

Z
Atomic number ()
n
Principal n ()
a_0
Bohr radius (Å)
r_n
Orbit radius (Å)

Lecture brief

Historical brief

Balmer, Rydberg, Bohr (1913), fine structure, Zeeman and Stern–Gerlach built the spectrum of one atom. The lab computes levels, selection and magnetic splitting. This sheet (ATM-03 — Bohr radius) is the form associated with Bohr radius. Working symbols: ZZ, nn \rightarrow a0a_0, rnr_n. The only length that SI constants allow for hydrogen. Expectation ⟨r⟩_{nℓ} is a bit larger.

Purpose

Purpose: compute a0a_0, rnr_n from ZZ, nn in Atomic physics via rn=n2a0/Z,a0=4πε02/me2r_n=n^2 a_0/Z,\quad a_0=4\pi\varepsilon_0\hbar^2/me^2 a₀ = 4π ε₀ ħ² / (m e²) ≈ 0.529 Å, r_n = n² a₀ / Z. Use it when a real atomic physics question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given Z=1.000Z = 1.000\,\mathrm{—}, n=1.000n = 1.000\,\mathrm{—}, the governing relation rn=n2a0/Z,a0=4πε02/me2r_n=n^2 a_0/Z,\quad a_0=4\pi\varepsilon_0\hbar^2/me^2 yields a0=0.5292A˚a_0 = 0.5292\,\mathrm{Å}, rn=0.5292A˚r_n = 0.5292\,\mathrm{Å}. A nucleus, a growing n-shell. Move a slider: the numbers are this situation, not a canned story.

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Inputs

Outputs

  • Bohr radius a_00.5292 Å
  • Orbit radius r_n0.5292 Å
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ATM-03 · quantum
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Narration of this film

A nucleus, a growing n-shell.

The only length that SI constants allow for hydrogen. Expectation ⟨r⟩_{nℓ} is a bit larger.

Reading speed

Watch on YouTube