INGENIA

ATM-26

Bohr energy

Hydrogen-like levels.

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AtomicBohr

Governing equation

En=−13.6Z2/n2 eVE_n=-13.6 Z^2/n^2~\mathrm{eV}

n∈[1,8]n \in \left[1, 8\right]

where

Z
Z (—)
n
n (—)
E_n
Energy (eV)

The figure, part by part

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ATM-26 · quantum
00:0 / 00:08
①

Governing law — red

En=−13.6Z2/n2 eVE_n=-13.6 Z^2/n^2~\mathrm{eV}

n∈[1,8]n \in \left[1, 8\right]

n=1n = 1En=−13.6E_n = -13.6

②

Domain of the variable — blue

nmin⁡=1,nmax⁡=8n_{\min} = 1,\quad n_{\max} = 8

n∈[1,8]n \in \left[1, 8\right]

n=1n = 1n=1n = 1

③

Response curve — green

En=−13.6Z2/n2 eVE_n=-13.6 Z^2/n^2~\mathrm{eV}

n∈[1,8]n \in \left[1, 8\right]

n=1n = 1En=−13.6E_n = -13.6

④

Rate of change — amber

dEndn\frac{\mathrm{d}E_n}{\mathrm{d}n}

n∈[1,8]n \in \left[1, 8\right]

n=1.044n = 1.044En′=23.99E_n^{\prime} = 23.99

Lecture brief

Historical brief

Balmer, Rydberg, Bohr (1913), fine structure, Zeeman and Stern–Gerlach built the spectrum of one atom. The lab computes levels, selection and magnetic splitting. This sheet (ATM-26 — Bohr energy) is the form associated with Bohr. Working symbols: ZZ, nn →\rightarrow EnE_n. Hydrogen-like levels.

Purpose

Purpose: compute EnE_n from ZZ, nn in Atomic physics via En=−13.6Z2/n2 eVE_n=-13.6 Z^2/n^2~\mathrm{eV} Hydrogen-like levels. Use it when a real atomic physics question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given Z=1.000 —Z = 1.000\,\mathrm{—}, n=1.000 —n = 1.000\,\mathrm{—}, the governing relation En=−13.6Z2/n2 eVE_n=-13.6 Z^2/n^2~\mathrm{eV} yields En=−13.600 eVE_n = -13.600\,\mathrm{eV}. Hydrogen-like levels. Move a slider: the numbers are this situation, not a canned story.

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Inputs

Outputs

  • Energy E_n-13.600 eV
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ATM-26 · quantum
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Narration of this film

Hydrogen-like levels.

Hydrogen-like levels.

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