INGENIA

AST-14

Luminosity distance (nearby)

d_L = (c / H₀) z (1 + z/2) in a matter-empty nearby expansion. Pedagogical.

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RadiationLuminosity distance

Governing equation

dL≈(c/H0)z(1+z/2)d_L\approx(c/H_0)z(1+z/2)

z∈[0.001,1.5]z \in \left[0.001, 1.5\right]

where

z
Redshift (—)
H_0
Hubble constant (km/s/Mpc)
d_L
Luminosity distance (Mpc)

The figure, part by part

Each numbered marker wears the color of its card. Hover a card to light the marker. Tap a marker to jump to that card. The slider walks a red point along the curve; Animate drawing traces it like a pen.

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①

Governing law — red

dL≈(c/H0)z(1+z/2)d_L\approx(c/H_0)z(1+z/2)

z∈[0.001,1.5]z \in \left[0.001, 1.5\right]

z=0.001z = 0.001dL=4.285d_L = 4.285

②

Domain of the variable — blue

zmin⁡=0.001,zmax⁡=1.5z_{\min} = 0.001,\quad z_{\max} = 1.5

z∈[0.001,1.5]z \in \left[0.001, 1.5\right]

z=0.001z = 0.001z=0.001z = 0.001

③

Response curve — green

dL≈(c/H0)z(1+z/2)d_L\approx(c/H_0)z(1+z/2)

z∈[0.001,1.5]z \in \left[0.001, 1.5\right]

z=0.001z = 0.001dL=4.285d_L = 4.285

④

Rate of change — amber

ddLdz\frac{\mathrm{d}d_L}{\mathrm{d}z}

z∈[0.001,1.5]z \in \left[0.001, 1.5\right]

z=0.01z = 0.01dL′=4327.4d_L^{\prime} = 4327.4

Lecture brief

Historical brief

Hubble expansion, Jeans collapse, Eddington luminosity, Bondi accretion and Stefan–Boltzmann stars are the first astrophysical budgets. The sheets scale a star, a cloud and a horizon. This sheet (AST-14 — Luminosity distance (nearby)) is the form associated with Luminosity distance. Working symbols: zz, H0H_0 →\rightarrow dLd_L. At very low z, d_L ≈ c z / H₀. Flux F = L / (4π d_L²).

Purpose

Purpose: compute dLd_L from zz, H0H_0 in Astrophysics via dL≈(c/H0)z(1+z/2)d_L\approx(c/H_0)z(1+z/2) d_L = (c / H₀) z (1 + z/2) in a matter-empty nearby expansion. Pedagogical. Use it when a real astrophysics question must be answered in SI before a code check.

Live realistic example

In symbols

Live case. Given z=0.050 —z = 0.050\,\mathrm{—}, H0=70.000 km/s/MpcH_0 = 70.000\,\mathrm{km/s/Mpc}, the governing relation dL≈(c/H0)z(1+z/2)d_L\approx(c/H_0)z(1+z/2) yields dL=219.49 Mpcd_L = 219.49\,\mathrm{Mpc}. A candle, a stretch, a dimming. Move a slider: the numbers are this situation, not a canned story.

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Inputs

Outputs

  • Luminosity distance d_L219.49 Mpc
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Narration of this film

A candle, a stretch, a dimming.

At very low z, d_L ≈ c z / H₀. Flux F = L / (4π d_L²).

Reading speed

Watch on YouTube